Answer:
The nth term is 109-9n
Step-by-step explanation:
Here, we want to find the nth term of the given arithmetic sequence
Mathematically, we have the nth term as;
Tn = a + (n-1)d
where a is the first term which is 100 in this case
d is the common difference which is the value obtained by subtracting the preceding term from the succeeding term; it is constant throughout the sequence
The value here is thus;
82-91 = 91-100 = -9
Substituting these values
Tn = 100 + (n-1)-9
Tn = 100 -9n + 9
Tn = 100 + 9 - 9n
Tn = 109-9n
6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. These are the zeroes.
Answer:
y = ac / (a - b - c)
Step-by-step explanation:
y(a - b) = c(y + a)
Distribute
ay - by = cy + ac
Subtract cy from both sides
ay - by - cy = ac
Factor out y
y(a - b - c) = ac
Divide both sides by (a - b - c)
y = ac / (a - b - c)
65/100 = 13/20
(divide by 5 on both sides)
Hope this helped!
