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antoniya [11.8K]
3 years ago
15

I need an equation of the line that passes through the given point and is parallel to the given line (6,-3);y=-2/3 x+5

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

<em>y = -2/3 x + 1</em>

Step-by-step explanation:

The line y = -2/3 x + 5 is in y = mx + b form, where m is the slope, so the slope of the given line is -2/3. Parallel lines have equal slopes, so the equation you are looking for also has slope -2/3.

The parallel line has equation

y = -2/3 x + b

We need to find b.

Since we are given a point, we substitute x and y with the x- and y-coordinates of the given point and solve for b. x = 6, and y = -3.

y = -2/3 x + b

-3 = (-2/3)(6) + b

-3 = -4 + b

1 = b

Now that we know b = 1, we can write the equation.

y = -2/3 x + b

y = -2/3 x + 1

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