Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere

The differential of V with respect to r is:

dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
Answer:
3/2y -5
Step-by-step explanation:
-1/2 (-3y+10)
Distribute
-1/2* -3y + -1/2*10
3/2y -5
PROBABILITY = 11 letters
VOWELS + T = A, E, I, O, U, Y, T = 7
P=7/11
-19.6 m/s
Do you need the math as well?