There are 12 boys and 21 girls for a total of 33 students
I’m not sure if this is right!
Answer:
How to solve your problem
−
7
2
−
2
2
+
3
−
2
+
5
3
−
2
-7y^{2}-2y^{2}+y^{3}y-2y+5y^{3}-2y
−7y2−2y2+y3y−2y+5y3−2y
Simplify
1
Combine exponents
−
7
2
−
2
2
+
3
−
2
+
5
3
−
2
-7y^{2}-2y^{2}+{\color{#c92786}{y^{3}y}}-2y+5y^{3}-2y
−7y2−2y2+y3y−2y+5y3−2y
−
7
2
−
2
2
+
4
−
2
+
5
3
−
2
-7y^{2}-2y^{2}+{\color{#c92786}{y^{4}}}-2y+5y^{3}-2y
−7y2−2y2+y4−2y+5y3−2y
2
Combine like terms
−
7
2
−
2
2
+
4
−
2
+
5
3
−
2
{\color{#c92786}{-7y^{2}}}{\color{#c92786}{-2y^{2}}}+y^{4}-2y+5y^{3}-2y
−7y2−2y2+y4−2y+5y3−2y
−
9
2
+
4
−
2
+
5
3
−
2
{\color{#c92786}{-9y^{2}}}+y^{4}-2y+5y^{3}-2y
−9y2+y4−2y+5y3−2y
3
Combine like terms
−
9
2
+
4
−
2
+
5
3
−
2
-9y^{2}+y^{4}{\color{#c92786}{-2y}}+5y^{3}{\color{#c92786}{-2y}}
−9y2+y4−2y+5y3−2y
−
9
2
+
4
−
4
+
5
3
-9y^{2}+y^{4}{\color{#c92786}{-4y}}+5y^{3}
−9y2+y4−4y+5y3
4
Rearrange terms
−
9
2
+
4
−
4
+
5
3
{\color{#c92786}{-9y^{2}+y^{4}-4y+5y^{3}}}
−9y2+y4−4y+5y3
4
+
5
3
−
9
2
−
4
{\color{#c92786}{y^{4}+5y^{3}-9y^{2}-4y}}
y4+5y3−9y2−4y
Solution
4
+
5
3
−
9
2
−
4
Answer:
3069
Step-by-step explanation:
q=6/3=2
s10=3(2^10-1)÷(2-1)=3×(1024-1)=
3069
because sn=a1(q^n-1)/(q-1)
C. 52
Work:
(5x - 22) + (4x + 4) = 90
9x - 18 = 90
9x = 108
x = 12
4(12) + 4 =
48 + 4 = 52