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Troyanec [42]
4 years ago
8

I need to make this into an ionic equation with State symbols​

Chemistry
1 answer:
Shkiper50 [21]4 years ago
6 0

Answer:

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

Explanation:

There are three steps you must follow. You must write the:

  • Molecular equation
  • Ionic equation
  • Net ionic equation

A. Molecular equation

Pb(NO₃)₂(aq) + 2KI(aq) ⟶ PbI₂(s) + 2KNO₃(aq)

B. Ionic equation

You write all the soluble substances as ions.

Pb²⁺(aq)+ 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

Pb²⁺(aq) + <u>2NO₃⁻(aq) </u>+ <u>2K⁺(aq)</u> + 2I⁻(aq) ⟶ PbI₂(s) + <u>2K⁺(aq)</u> + <u>2NO₃⁻(aq</u>)

The net ionic equation is

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

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