Answer:
![-112.7 m/s^2](https://tex.z-dn.net/?f=-112.7%20m%2Fs%5E2)
Explanation:
We start by calculating the speed of the egg when it touches the upper surface of the carpet. This can be done by using the law of conservation of energy: in fact, the initial gravitational potential energy of the egg is converted into kinetic energy at the moment of impact, so we can write
![U=K\\mgh = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=U%3DK%5C%5Cmgh%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
where
m is the mass of the egg
is the acceleration of gravity
h = 0.35 m is the initial height of the egg
v is the speed as it touches the carpet
Solving for v,
![v=\sqrt{2gh}=\sqrt{2(9.8)(0.35)}=2.6 m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2gh%7D%3D%5Csqrt%7B2%289.8%29%280.35%29%7D%3D2.6%20m%2Fs)
Now we analyze the motion of the egg through the carpet. The minimum acceleration will be obtained when the egg cover the whole tickness of the carpet to stop, that is
s = 3.0 cm = 0.03 m
And the egg must stop after covering this distance, so the final velocity will be
v' = 0
To find the acceleration, we can use the suvat equation:
![v'^2-v^2=2as](https://tex.z-dn.net/?f=v%27%5E2-v%5E2%3D2as)
and solving for a,
![a=\frac{v'^2-v^2}{2s}=\frac{0^2-2.6^2}{2(0.03)}=-112.7 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv%27%5E2-v%5E2%7D%7B2s%7D%3D%5Cfrac%7B0%5E2-2.6%5E2%7D%7B2%280.03%29%7D%3D-112.7%20m%2Fs%5E2)
Answer:
Only the speed is constant.
The acceleration and velocity are changing.
Explanation:
The velocity of an object refers to its speed in a specific direction. Due to the fact that the car is driving in a circle, the direction of the car is changing. This makes the car not to have a constant velocity as this value changes each time the car makes a bend on the circular path. <em>(which is pretty much all the time).</em>
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The acceleration is a direct derivative of the velocity of the car. As a result, if the velocity is changing, the acceleration is also changing.
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Speed is a scalar quantity. This means it does not deal with the direction of the car. It only deals with how fast the car is moving. The car is on cruise control. this means that the speed of the car does not change.
Answer:
Great question! To solve this problem you just need a bit of simple math. The short answer is 60 m/s
Explanation:
To solve this, you must first set up your equation.
540km/2.5hr * 1000m/3600s
You would set it up this way because there are 1000 meters in a km and 3600 seconds in an hour. This
540000m/9000s
This simplifies down to
60m/s
Answer:
See the explanation below.
Explanation:
The units of work are consistent since if we work in the international system of measures we have the following dimensional quantities for velocity, distance and time.
s = displacement [m]
v and u = velocity [m/s]
t = time [s]
Now using these units in the given equation.
![s = 0.5*([m/s]+[m/s])*[s]\\s=0.5*[m/s]*[s]\\s = 0.5*[m]](https://tex.z-dn.net/?f=s%20%3D%200.5%2A%28%5Bm%2Fs%5D%2B%5Bm%2Fs%5D%29%2A%5Bs%5D%5C%5Cs%3D0.5%2A%5Bm%2Fs%5D%2A%5Bs%5D%5C%5Cs%20%3D%200.5%2A%5Bm%5D)
So the expression is good, and dimensional has consistency.