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dmitriy555 [2]
2 years ago
15

The speed of a wave is 2ms, and its wavelength 0.4 meters. What is the period of the wave?

Physics
2 answers:
AnnyKZ [126]2 years ago
6 0

Answer:

5

Explanation:

labwork [276]2 years ago
4 0

Answer:

8

Explanation:

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A neutral boron atom has 6 neutrons and 5 electrons. How many protons does it have? Select one: a. 7 b. 6 c. 5 d. 4
Ksivusya [100]
If the atom is neutral, it has the same number of protons as electrons. If there are 5 electrons, there are also 5 protons.
4 0
3 years ago
Convert the speed of light 3.0x10^8 m/s to km/day
Aleksandr [31]

Answer: 2.592 \times 10^{8}km/day

1 m = 0.001 km\\ 1 s= 1.157\times10^{-5} days\\ 1 m/s = \frac {0.001}{1.157\times10^{-5}} km/day = 86.4 km/day \\ 3.0\times 10^{8} m/s = 3.0\times 10^{8} m/s \times \frac {86.4 km/day}{1m/s} =2.592 \times 10^{8}km/day



7 0
3 years ago
Read 2 more answers
Tommy was walking at a rate of 4 miles hour at noon and at 12:30 pm he was walking at a brisk rate of 6 miles hour . Two hours l
maks197457 [2]

Answer:

B) Tommy had a positive acceleration between noon and 12:30 pm.

Explanation:

Acceleration is defined as the rate of change of velocity:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time

In the problem,

- At noon, Tommy is walking at a velocity of 4 mi/h

- At 12.30 pm, Tommy is walking at a velocity of 6 mi/h

- A time of half an hour (0.5 h) passed between the two moments

So Tommy's acceleration is

a=\frac{6 mi/h-4 mi/h}{0.5 h}=4 mi/h^2

and the acceleration is positive, since the velocity has increased.

3 0
3 years ago
Read 2 more answers
What would most likely happen if the power lines in a pretroleum power plant were broken
tatiyna
If a power lines in a petroleum power plant were broken CUSTOMERS WOULD NOT RECEIVE ELECTRICITY.
Power lines are used in electrical power transmission to transmit electrical energy across large distances. When these lines are broken, the generating plant will not be able to send electricity across to the consumers.
4 0
3 years ago
Car a is heading north with a velocity of 14 m/s. car b is traveling north also, with a velocity of 19 m/s. what is the relative
kicyunya [14]
a.)  Relative velocity = velocity of car B - velocity of car A
                             = 19 - 14
                             = 5 m/s
Hope this cleared your doubt, feel free to ask any question regarding this and have a nice day ahead! :)
6 0
3 years ago
Read 2 more answers
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