s=1/2(u+v)t check the dimensional consistency for this? where s is displacement, t is time, u is initial velocity, v is final ve
1 answer:
Answer:
See the explanation below.
Explanation:
The units of work are consistent since if we work in the international system of measures we have the following dimensional quantities for velocity, distance and time.
s = displacement [m]
v and u = velocity [m/s]
t = time [s]
Now using these units in the given equation.
So the expression is good, and dimensional has consistency.
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The acorn was at a height of <u>4.15 m</u> from the ground before it drops.
The acorn takes a time t to fall through a distance h₁, which is the length of the scale. When the acorn reaches the top of the scale, its velocity is u.
Calculate the speed of the acorn at the top of the scale, using the equation of motion,
Since the acorn falls freely under gravity, its acceleration is equal to the acceleration due to gravity g.
Substitute 2.27 m for s (=h₁), 0.301 s for t and 9.8 m/s² for a (=g).
If the acorn starts from rest and reaches a speed of 6.067 m/s at the top of the scale, it would have fallen a distance h₂ to achieve this speed.
Use the equation of motion,
Substitute 6.067 m/s for v, 0 m/s for u, 9.8 m/s² for a (=g) and h₂ for s.
The height h above the ground at which the acorn was is given by,
The acorn was at a height <u>4.15m</u> from the ground before dropping down.