Hi there!
Use the following equation: (Newton's Second Law)
∑F = ma, where:
∑F = net force (J)
m = mass (kg)
a = acceleration (m/s²)
Plug in the given values:
∑F = 1500 · 40 = <em>60,000 J</em>
Answer:
I think is o or mavey it could be D
Answer:
Explanation:
a ) y = A sin(B) ; here B is the phase of the wave which moves so that it remains constant
ωt - kx = constant
differentiating on both sides
ωdt - kdx =0
ωdt = kdx
dx / dt = ω / k
wave velocity = ω / k
b ) ω = 14.5 rad / s ,
k = 18 rad / m
wave velocity = ω / k
= 14.5 / 18
= .805 m /s
80.5 cm / s
c )
Amplitude = A
= 9.5 m
The net force that is applied to the passenger during the elevator acceleration is 218.75 N.
<h3>What is net force?</h3>
This is the single force obtained from the combinatiion of two or more forces
To calculate the net force that is applied to the passenger during the elevator's acceleration, we use the formula below.
Formula:
- F = m(v-u)/t............ Equation 1
Where:
- F = force
- m = mass
- v = Final velocity
- u = initial velocity
- t = time.
From the question,
Given:
- m = 70 kg
- u = 0 m/s
- v = 12.5 m/s
- t = 4 s
Substitute these values into equation 1
Hence, The net force that is applied to the passenger during the elevator acceleration is 218.75 N.
Learn more about net force here: brainly.com/question/13370981