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sattari [20]
3 years ago
8

The sum of 4 consecutive odd numbers is 40. What is the second number in this sequence?

Mathematics
2 answers:
Tcecarenko [31]3 years ago
7 0

Answer:

7,9,11,13 = 40

Step-by-step explanation:

second number is 9

zaharov [31]3 years ago
7 0

Answer:

9

Step-by-step explanation:

Let's call the numbers x, x+2, x+4, x+6

the sum is 40 which is 3x + 12 = 40

3x = 40 - 12

3x = 28

x = 7

The second number is x + 2 ➡ 7 + 2 = 9

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80 - [50 - {20 ÷ 2 – (16 - 2÷ 2) ÷ 3}]
trapecia [35]

Answer:

35

Step-by-step explanation:

We have to solve the problems in the parenthesis first.

(16-2÷2)= (16-1)=(15)

20÷2-15÷3

(20÷2)-(15÷3)

10-5=5

50-5= 45

80-45= 35

Hope this helps!

6 0
3 years ago
What fraction is bigger 5/8 or 7/15
Zolol [24]
5/8=.625 and 7/15=.466 repeating so 5/8 is a bigger fraction
6 0
3 years ago
Read 2 more answers
Consider the following functions.G(x) = 4x2; f(x) = 8x(a)
noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form 4x^2+C is an antiderivative of 8x

Step-by-step explanation:

A function <em>F </em>is an antiderivative of the function <em>f</em> if

F'(x)=f(x)

for all x in the domain of <em>f.</em>

(a) If f(x) = 8x, then G(x)=4x^2 is an antiderivative of <em>f </em>because

G'(x)=8x=f(x)

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.

(b) Because

\frac{d}{dx}(4x^2)=8x

then G(x)=4x^2 is an antiderivative of f(x) = 8x. Therefore, every antiderivative of 8x is of the form 4x^2+C for some constant C, and every function of the form 4x^2+C is an antiderivative of 8x.

8 0
3 years ago
Write the domain &amp; range of the function using interval notation.
fgiga [73]
Option A will be the correct answer
5 0
3 years ago
The lengths, in minutes, of the movies currently showing at a movie theater are shown in the data set. ​ ​ ​ ​Create a histogram
alexdok [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required lengths are not given.

I will use the following data set to answer the question.

Dataset: 35, 51, 39, 42, 68, 62, 32, 59

First, is to determine the range of the dataset

Range = Highest - Least

Range = 68 - 32

Range = 36

Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval

Class= Range/10

Class = 36/10

Class = 3.6

Class \approx 4

<em>So, we use 4 classes</em>

Plot the frequency distribution table as follows:

\begin{array}{ccc}{Intervals} & {Observations} & {Frequency} & {31-40} & {32,35,39} & {3} & {41-50} & {42} & {1} & {51-60} & {51,59} & {2} & {61-70} & {62,68} & {2}\ \end{array}

<em>See attachment for histogram</em>

5 0
3 years ago
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