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k0ka [10]
3 years ago
13

100 points will mark BRAINLYEST

Mathematics
1 answer:
asambeis [7]3 years ago
5 0

Prompt - Select an image of an art work from smarthistory by looking at the "Histories of Art" tab.

Objective - This is an exercise to get comfortable with applying the language of art as well as the steps of the Art Analysis ChartActions (summarized below).

You must include in this exercise four short, clearly separated paragraphs (2-3 sentences) consisting of the concerns printed in bold:

1. description of the chosen image (include the image information: title, artist's name, year, medium, etc.) and say what you see.

2. analysis of what you see by saying what each element is achieving (e.g. "converging lines are used to draw our attention to the focal point.")

3. interpretation of the image by saying what the work is about and what it means.

4. evaluation of the image by talking about where you think the "value" lies in your chosen image, and explain why. The term value here is not in the context of light or dark as in formal attributes. It refers to what is significant in the work of art you are analyzing, and how successful or unsuccessful it has been executed. Evaluation here is an exercise in reasoning/arguing based on your previous three paragraphs.

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Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )
Gemiola [76]

QUESTION 1

The given inequality is

|m|-2>0

We group like terms to get,

|m|>2


This implies that,

-m>2 or m>2.

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We can write this interval notation to get,

(-\infty,-2)\cup (2,+\infty).


QUESTION 2

|x-4|-3\:>\:5.

We group like terms to get,


|x-4|\:>\:5+3.


|x-4|\:>\:8

We split the absolute value sign to get,

-(x-4)\:>\:8 or x-4\:>\:8


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x-4\: or x-4\:>\:8


x\: or x\:>\:8+4


x\: or x\:>\:12


We can write this interval notation to get,

(-\infty,-4)\cup (12,+\infty).


QUESTION 3

The given inequality is

|6+9x|\leq 24


We split the absolute value sign to obtain,

-(6+9x)\leq 24 or (6+9x)\leq 24


This simplifies to

6+9x\ge -24 and 6+9x\leq 24


9x\ge -24-6 and 9x\leq 24-6


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x\ge -\frac{10}{3} and x\leq 2

-\frac{10}{3}\leq x\leq2

We write this in interval form  to get,

[-\frac{10}{3},2]


QUESTION 4

The given inequality is

|1-5a|>29

We split the absolute value sign to get,

-(1-5a)>29 or 1-5a>29

This simplifies to,

1-5a\: or 1-5a\:>\:29


This implies that,

-5a\: or -5a\:>\:29-1


-5a\: or -5a\:>\:28


a\:>\:6 or a\:

We write this in interval notation to get,

(-\infty,-\frac{28}{5})\cup (6,+\infty)















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Answer:

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Here the factors are given in the type (x+)(x−)

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Option A is the correct answer.            

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