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sergij07 [2.7K]
3 years ago
8

Subtract.

Mathematics
1 answer:
ycow [4]3 years ago
3 0
-27 - (-3) = -27 + 3 = - 24

560 - 2(25 + 11) = 560 - 2(36) = 560 - 72 = 488

8y - x^2....x = -5, y = 4
8(4) - (-5)^2 =
32 + 5^2 =
32 + 25 =
57
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Please answer correctly !!!!! Will mark brainliest !!!!!!!!!
Brut [27]

Answer:

The width is 2x+1

Step-by-step explanation:

10x^2 +5x

Divide this by 5x

10x^2 /5x = 2x

+

5x/5x =1

Add this together

2x+1

The width is 2x+1

5 0
3 years ago
Read 2 more answers
Estimate what is 31.75÷8= you have to estimate tho
Afina-wow [57]
If you estimate, its around 5
5 0
3 years ago
The calculated average of a data set best describes which of the following? (4 points) Group of answer choices Mean Median Mode
OleMash [197]

Answer:

Its A: Mean

Step-by-step explanation:

Mean means average in a set of data

8 0
3 years ago
There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
Find the domain of the rational function 9x/(x+5)(x+3)
xenn [34]

Answer:

the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[

Step-by-step explanation:

hello :

f(x) = 9x/(x+5)(x+3)

f exist for : (x+5)(x+3) ≠ 0

(x+5)(x+3)=0

x+5=0 or x+3=0  means : x= - 5 or x= -3

the domain is : D = ]-∞ , -5[ U ]-5 , -3[ U ]-3 , +∞[

7 0
3 years ago
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