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sergij07 [2.7K]
4 years ago
8

Subtract.

Mathematics
1 answer:
ycow [4]4 years ago
3 0
-27 - (-3) = -27 + 3 = - 24

560 - 2(25 + 11) = 560 - 2(36) = 560 - 72 = 488

8y - x^2....x = -5, y = 4
8(4) - (-5)^2 =
32 + 5^2 =
32 + 25 =
57
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How can I solve this problem?
Rus_ich [418]
(f+g)(x)=0
f (x) + g (x)=0

now,
substitute their values

x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0


we have to find it's zeroes (or roots) now:

x-6 =0
x = 6


x +3 =0
x = -3
7 0
4 years ago
Which expressions represent the difference of exactly two expressions?
torisob [31]

Answer:

Step-by-step explanation:

The answer is acd

4 0
3 years ago
Solve for x.<br><br> 5x – 10 &gt; 20 or 5x – 10 ≤ –15
slava [35]
For the one it

X>6


For the second one it’s x ≤ −1
5 0
3 years ago
Someone please help me w this standard form question​
svp [43]

Answer:

2.4 × 10⁶

Step-by-step explanation:

Given:

  • \sf x=3.8 \times 10^5
  • \sf y=5.9 \times 10^4

To calculate the value of R, substitute the given values into the given formula:

\begin{aligned}\sf R & = \sf \dfrac{x^2}{y}\\\\ \implies \sf R& = \sf \dfrac{(3.8 \times 10^5)^2}{5.9 \times 10^4}\\\\& = \sf \dfrac{3.8^2 \times (10^5)^2}{5.9 \times 10^4}\\\\& = \sf \dfrac{14.44 \times 10^{10}}{5.9 \times 10^4}\\\\& = \sf \dfrac{14.44}{5.9} \times \dfrac{10^{10}}{10^4}\\\\& = \sf 2.4474... \times 10^{(10-4)}\\\\& = \sf 2.4474... \times 10^6\\\\\end{aligned}

Therefore, the value of R to 1 decimal place is 2.4 × 10⁶

--------------------------------------------------------------------------

<u>Exponent Rules used</u>

(a^b)^c=a^{bc}

{a^b}{a^c}=a^{b-c}

3 0
2 years ago
Read 2 more answers
16-11-13-5-10 2-15-18 13-23 8-11-17 11-12 22-11-12-19 decode message
Katen [24]

Answer:

16-11-13-5-10 => P-K-M-E-J

2-15-18 => B-O-R

13-23 = > M-W

8-11-17 => H-K-Q

11-12 => K-L

22-11-12-19 => V-K-L-S

Step-by-step explanation:

Given

See attachment for code key

Required

Decode

16-11-13-5-10

2-15-18

13-23

8-11-17

11-12

22-11-12-19

From the code key, we can see that each number represent the alphabet at that position;

To do this, we simply replace each number with the alphabet they represent.

So, we have:

16-11-13-5-10 => P-K-M-E-J

2-15-18 => B-O-R

13-23 = > M-W

8-11-17 => H-K-Q

11-12 => K-L

22-11-12-19 => V-K-L-S

4 0
3 years ago
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