All categories

3 years ago

What are the multiples of 9 that are less than 80?

Mathematics

2 answers:

motikmotik3 years ago

6 0

9,18,27,36,45,54,63,72

choli [55]3 years ago

3 0

In order to answer the question, you need to know what a multiple is. A multiple is a number which can be divided by the original number without a remainder.
So for example multiples of 5 include: 5, 10, 15, 20, 25, etc... you are basically adding 5 each time. So in this question, you are being asked to list what the multiples of 9 are that are less than 80. You begin by listing the multiples of 9 and stop once you get to 80.

9,18, 27, 36, 45, 54, 63, 72, 81. You stop here because the last multiple of 9 that you listed is more than 80. So your answer to this question would be:
9,18, 27, 36, 45, 54, 63, 72.

You might be interested in

Plz help! Big points!

Mama L [17]

Answer:

1209

Step-by-step explanation:

v= pi* r^2* h r= d/2

soda:

d = 2 r = 1

h = 5

grabage:

d = 24 r = 12

h = 42

volume G: 19000.35

volume S: 15.71

volume G/ Volume S = # of soda cans

8 0

3 years ago

Expand the following: c) 4(2x +1)

murzikaleks [220]

Answer:

= 4(2x +1)

= 4× 2x + 4×1

= 8x +4

6 0

3 years ago

Read 2 more answers

357 Miles in 5 hours ____miles per hour Find until rate

Mandarinka [93]

71.4 and to check just multiply 71.4 times 5 and it'll get 357

8 0

3 years ago

What is the relationship between 0.04 and 0.004?

Nimfa-mama [501]

We have to determine the relationship between 0.04 and 0.004. The first number, 0.04 is 4 hundredths and the secind number ( 0.004 ) is 4 thousanths. Therefore 0.04 is larger than 0.004. if we divide 0.04 : 0.004 = 40 : 4 = 10. Answer : 0.04 is 10 times greater than 0.004.

4 0

3 years ago

National statistics show that 23% of men smoke and 18.5% of women smoke. A random sample of 175 men indicated that 45 were smoke

NeTakaya

Answer:

98% C.I. = [-0.1270, 0.0994]

Step-by-step explanation:

Here

p1= proportion of men smokers

p1= 45/175= 0.2571

p2= proportion of women smokers

p2= 42/155= 0.2709

1) Choose the significance level ∝= 0.02

2) The formula for confidence interval is

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

and

(p1^- p2^) z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

3) The z value is 2.05

4) Calculations:

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(-2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=-0.1270 ( using calculator)

And

(p1^- p2^)z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=0.0994 ( using calculator)

and Putting ± 2.05 in the confidence interval formula we get limits (-0.1270, 0.0994)

6 0

3 years ago