now that we know what are the x-values, what are the y-values? well, we can just use the 2nd equation, since we know that y = x - 28, then
![\bf y = x - 28\implies \stackrel{\textit{when x = 16}}{y = 16 - 28}\implies y = -12 \\\\\\ y = x - 28\implies \stackrel{\textit{when x = 12}}{y = 12 - 28}\implies y = -16 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{x}{16}~~,~~\stackrel{y}{-12})\qquad,\qquad (\stackrel{x}{12}~~,~~\stackrel{y}{-16})~\hfill](https://tex.z-dn.net/?f=%5Cbf%20y%20%3D%20x%20-%2028%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bwhen%20x%20%3D%2016%7D%7D%7By%20%3D%2016%20-%2028%7D%5Cimplies%20y%20%3D%20-12%20%5C%5C%5C%5C%5C%5C%20y%20%3D%20x%20-%2028%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bwhen%20x%20%3D%2012%7D%7D%7By%20%3D%2012%20-%2028%7D%5Cimplies%20y%20%3D%20-16%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%28%5Cstackrel%7Bx%7D%7B16%7D~~%2C~~%5Cstackrel%7By%7D%7B-12%7D%29%5Cqquad%2C%5Cqquad%20%28%5Cstackrel%7Bx%7D%7B12%7D~~%2C~~%5Cstackrel%7By%7D%7B-16%7D%29~%5Chfill)
Answer:
diameter times height times x = volume
Step-by-step explanation:
using the length times width times height equation for volume.
good luck :)
Answer:
14
Step-by-step explanation:
The question is asking for the value of A when n = 2
So we just need to plug in 2 for n
A(2) = 10 + (<em>2</em>-1)(4) = 10 + (1)(4) = 10 +4 = 14
Answer:
306.324
306.359
316.011
Step-by-step explanation:
Hope it helped!
Because the angle is a straight angle, it means that the total of DEC and CEF would be 180º. (CEF + DEF = 180º) With this information we can make the equasion:
(11x - 12) + (2x + 10) = 180
first, to find x:
to simplify (11x - 12) + (2x + 10) = 180, you add the two equations:
13x - 2 = 180
13x = 182
x = 182/13
x = 14
Now, insert the x (which we found that is 14) to each equation.
DEC: (11 x 14 - 12)
= 154 - 12 = 142
m DEC is 142º.
CEF: (2 x 14 + 10)
=28 + 10 = 38
m CEF is 38º.
<em>check: (CEF + DEC = 180º)</em>
<em>38 + 142 = 180 </em>
therefore, the answers are correct :D
