Answer:
good news, the second one is relatively easy because it can be factored to (2x+1)(2x-3) which means that number two has solutions of -1/2 and 3/2
but for number one you have to either use the quadratic equation cause I've tried using synthetic division or just use the second equation to derive the first solutions so I tried move the graph up by two units and found that the intercepts are approximately (1+-√2)/2 or 1/2+-1/√2 for 4x^2-4x-1
Answer:
The mean and standard deviation of Y is $6.56 and $2.77 respectively.
Step-by-step explanation:
Consider the provided information.
Let Y represent their profit on a randomly selected pizza with this promotion.
The company is going to run a promotion where customers get $2 off any size pizza.
Therefore, 

So the mean will be reduced by 2.



If we add or subtract any constant number from a given distribution, then the mean is changed by the same number(i.e constant number) but the standard deviation will remain the same.
Therefore 
Hence, the mean and standard deviation of Y is $6.56 and $2.77 respectively.
Given:
Cylinder: radius = 8 yd; height = 4 yd
Surface Area = 2 π r h + 2 π r²
SA = 2 * 3.14 * 8 yd * 4yd + 2 * 3.14 * (8yd)²
SA = 200.96 yd² + 401.92 yd²
SA = 602.88 yd²
Volume = π r² h
V = 3.14 * (8yd)² * 4yd
V = 803.84 yd³
Dimension is cut in half. radius = 4yds ; height = 2yds
S.A = 2 * 3.14 * 4yd * 2yd + 2 * 3.14 * (4yd)²
S.A = 50.24 yd² + 100.48 yd²
SA = 150.72 yd²
V = 3.14 * (4yd)² * 2yd
V = 100.48 yd³
SA = 602.88 yd² - 150.72yd² = 452.16 yd²
V = 803.84 yd³ - 100.48 yd³ = 703.36 yd³
Answer:
Perimeter of the final star = 40 cm²
Step-by-step Explanation:
The perimeter of the six-pointed star is the sum of the sides of the 6 equilateral triangles that form a boundary around the star.
1 triangular tiles gas a perimeter of 10cm.
Only 2 out of the 3 equal sides of each of the 6 equilateral triangles form the boundary of the final star.
Therefore, perimeter of the final star = ⅔ of the total perimeter of 6 triangular tiles
= ⅔ of (10*6)
= ⅔*60
= 2*20
Perimeter of the final star = 40 cm²
Answer:
b
Step-by-step explanation: