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2 years ago

I need help solving this in simplest form

Mathematics

1 answer:

Simora [160]2 years ago

3 0

Think of the 7 as if it's a fraction (over one)

7 9

_ X 3 _ =

1 14

then we make it all a fraction so (14 × 3)+9 all over 14 which then = 51 over 14

7 51 51 1

__ × __ = __ = 25 _ or in decimal form 25.5

1 14 2 2

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Step-by-step explanation:

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Read 2 more answers

For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.

Flauer [41]

$\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\$

$\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276$

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Since the second 4 is two decimal points away from the first 4, the answer should be 100 (two zeros)

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