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valentinak56 [21]
2 years ago
10

I need help solving this in simplest form

Mathematics
1 answer:
Simora [160]2 years ago
3 0

Think of the 7 as if it's a fraction (over one)

7                 9

_      X  3    _     =          

1                 14



then we make it all a fraction so (14 × 3)+9 all over 14 which then = 51 over 14

     7            51           51                 1

    __     ×    __   =     __    =   25   _     or in decimal form 25.5

      1            14            2                 2

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snow_lady [41]

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

Step-by-step explanation:

Given equation is C=\frac{5}{9}(F -32)

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=0.

For F = 41.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(41 -32)

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For F = 50.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(50 -32)

C=10

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The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

C=15

<em>Note: The figure shows a graph of given equation with points.</em>

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C=\frac{5}{9}(F -32)

C=\frac{5}{9}(32 -32)

<em>C=18.333333.</em>

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C=\frac{5}{9}(F -32)

0=\frac{5}{9}(F -32)

0=(F -32)

F=32 Temperature.

Ans D). Slope of the line C=\frac{5}{9}(F -32)

The slope of line is given by s= \frac{Y1-Y2}{X1-X2}

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= \frac{Y1-Y2}{X1-X2}

s= \frac{0-5}{32-41}

s= \frac{5}{9}

Slope of line C=\frac{5}{9}(F -32) is \frac{5}{9}

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