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ElenaW [278]
3 years ago
14

Which ordered pair could be removed to make relation a function

Mathematics
2 answers:
Kipish [7]3 years ago
8 0

Answer:

The answer is C,

Step-by-step explanation:

Hope this helps!!

Feliz [49]3 years ago
6 0
If the X are the same then remove it n it's a function
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Answer:

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Step-by-step explanation:

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x = -1 or x = -3

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Step-by-step explanation:

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katrin2010 [14]
\dfrac{n^2+3n+2}{n^2+6n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n^2+2n+n+2}{n^2+4n+2n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n(n+2)+1(n+2)}{n(n+4)+2(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{(n+2)(n+1)}{(n+2)(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{n+1}{n+4}-\dfrac{2n}{n+4}=\dfrac{n+1-2n}{n+4}=\dfrac{1-n}{n+4}

Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}
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Step-by-step explanation:

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