Answer:-8 is the first one.
Step-by-step explanation:-3(2)-2
-6-2
Hopefully this helps you understand the rest (and I was just too lazy to do all of them).
Answer:
10
Step-by-step explanation:
Means back the numbers into multiples of several small numbers
Like:; 1. We take LCM of 40
Just break into multiples of small number
40= 2×2×2×5
2. We take LCM of 50
50= 5×5×2
So LCM for 100 is 2×2×5×5
after that see the pairs in the LCM like 2×2 or 3×3 or 4×4(same numbers)
Then write the the single number in place of two multipled numbers
Like:; 2×2 is written as 2 // 3×3 is written as 3
So we can write 100 into 2×2×5×5 and then after selecting pairs (2×2)×(5×5)
write pairs in single number 2×5
And so we get 2×5=10
So we find root of 100 that is 10
Answer:
The month will be October again lol :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
This is a composite function, in which we will first evaluate the s function at a value of 2, then we will use that value in the t function.
s(2) = 5(2)+ 5 so
s(2) = 15. Now we evaluate the t function at 15:
t(15) = 3(15) + 4 so
t(15) = 49
Hello :
x²- 6x + 8 = x² - 2(3)(x) +8
= (x² -2(3)(x) +9) - 9 + 8
= ( x - 3 )² - 1²
= (x - 3 + 1 ) (x - 3 - 1 )
x²- 6x + 8 = (x - 2 ) ( x - 4 )
x - ∞ 2 4 + ∞
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x - 2 -------- 0 +++++ +++++++
x - 4 --------- -------- 0 +++++
(x - 2 ) ( x - 4 ) +++ 0 ------ 0 ++++++
x2 − 6x + 8 > 0 the solution in : ]-∞:2[ U ]4;+∞[
