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Naily [24]
3 years ago
10

Hey, can someone help me with this, please?

Mathematics
1 answer:
Pie3 years ago
3 0
If the area of the yard is 3a^2 and is also 7,500^2 then 3a^2=7,500^2

So we want to find what A is not 3a^2.

3a^2=7,500^2 now we square root both sides
3a=7,500 now we divide both sides by 3
a=2,500

And there you go a=2,500

Bainliest if this helped you?
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CAN SOMEONE PLEASE ANSWER THIS SOON! THANK YOU!
lyudmila [28]

We want to find one-half of the reciprocal of 7/sqrt(98). Let's write down an expression for this:

\dfrac{1}{2} \times \dfrac{\sqrt{98}}{7}

We can rewrite 98 into 2 \times 49

\dfrac{1}{2} \times \dfrac{\sqrt{2 \times 49}}{7}

=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times \sqrt{49}}{7}

The square root of 49 is 7

=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times 7}{7}

=\dfrac{1}{2} \times\sqrt{2}

=\dfrac{\sqrt{2}}{2}

This should be your answer. Let me know if you need any clarifications, thanks!

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Harlamova29_29 [7]

Answer:

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