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andriy [413]
4 years ago
9

4 divide by the square root of 2

Mathematics
2 answers:
xxTIMURxx [149]4 years ago
8 0

Answer: 2.82842712475

Step-by-step explanation:

Contact [7]4 years ago
7 0

Answer:

4/sqrt2 = roughly 2.8

Step-by-step explanation:

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Need help ASAP! Choose the numbers that are irrational. 1. 0. 87 repeating 2. 3.624 3. √2 4. 0. 6 repeating 5. -5 6. 1 over 3 7.
svp [43]

Answer:

√2, pi.

Step-by-step explanation:

An irrational number cannot be written as a fraction a/b where a and b are integers ( not = 0)..

3 0
3 years ago
What is 6 4/9 as an improper fraction
Katarina [22]

Answer: 58/9

Step-by-step explanation:

Turn 6 into an improper fraction.

6x9 = 54

54/9 + 4/9 = 58/9

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3 years ago
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Find the area of circle with diameter of 52 cm. Use ≈3.14. <br> The area of circle is approximately?
Likurg_2 [28]

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169.56

Step-by-step explanation:

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Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
15. True or False? In a recession or a depression, inflation will likely decrease.
IgorLugansk [536]

Answer:

a

Step-by-step explanation:

in a depression inflation is most likely to decrease

3 0
3 years ago
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