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Oxana [17]
3 years ago
12

An inserted graphic in Excel is

Computers and Technology
2 answers:
telo118 [61]3 years ago
7 0
<h2>Answer:</h2>

<u>An inserted graphic in Excel is </u><u>B. inserted in the active cell.</u>

<h2>Explanation:</h2>

A graphic is considered as any picture or shape present in the directory of any computer. So when you are working in an Excel worksheet and you insert any graphic so it means you have inserted a shape. It may be a line, picture or any other geometrical shape, then this image or graphic will be inserted in the cell which is active at that time and no where else. Therefore option B is the correct answer.

antoniya [11.8K]3 years ago
4 0

Answer:

B. inserted in the active cell.

Explanation:

In addition to being able to work with formulas, charts, filters, and many other features, Excel also enables the use of images. This can be very interesting if you need to streamline your spreadsheets or simply insert your company logo.

To insert an image into a cell in Excel, simply follow the steps below:

1. Go to Insert> Images tab

2. In the imagem Insert Image ‘dialog box, locate the images you want to insert into a cell in Excel.

3. Resize the image / image so that it fits perfectly in the cell.

4. Place the image in the cell.

A nice way to do this is to first press the ALT key and then move the image with the mouse. It will fit and arrange with the edge of the cell as it approaches it.

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Write a program, NumberStatistics.java, that reads an unspecified number of integers. The program ends with the input 0. The pro
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Answer:

Following are the program, which can be below:

import java.util.*; //defining header file

public class NumberStatistics  //defining class NumberStatistics

{

public static void main(String[] arc) //defining main method

{

int total_number=0,max_val=0,min_val=0,neg_val=0,pos_val=0,neg_count=0,pos_count=0,x; //defining variables

Scanner ox= new Scanner(System.in); //creating Scanner class Object

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x= ox.nextInt(); //input value from user

while(x!=0) //defining loop to check input value is 0

{

total_number++; // increment value

if(total_number == 1)  //defining conditional statement to check minimum and maximum value

{

max_val = x; //assign value in max  

min_val = x;//assign value in min

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else  //defining else block

{

if(max_val < x) //check maximum value

{

max_val = x; //assign maximum value

}

if(min_val > x) //check minimum value

{

min_val = x; //assign minimum value

}

}

if(x > 0) //input values  

{

pos_count++; //count positive value

pos_val+=x; // add positive values

}

else  

{

neg_count++;//count negative value

neg_val+=x; // add negative values

}

x = ox.nextInt(); //input values

}

// defining conditionl statement

if(total_number != 0)  // defining if block to print all value

{

System.out.println("positive value average= "+(pos_val/(double)pos_count));

System.out.println("negative values Average= "+(neg_val/(double)neg_count));

System.out.println("all values average= "+(pos_val+neg_val)/(double)total_number);

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else  

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System.out.println("no positive values found");

System.out.println("no negative values found");

}

}

}

Output:

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all values average= 4.0

maximum value = 22

minimum value = -22

Explanation:

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