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3 years ago

Hope an expert can help with this

Mathematics

1 answer:

Citrus2011 [14]3 years ago

5 0

For Range you take the biggest number and subtract it with the smallest. So:

January = E14,000

Febuary = E9,000

March = E10,000

All Three Months = E17,000

Hope this helps,pleeease vote as brainliest!

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lamont cotton is 4% comission on the first 10,000 of monthly sales mens 10% on all sales over 10,000. last month his 38,00. what

Pani-rosa [81]

Given:

Lamont cotton is 4% commission on the first 10,000 of monthly sales and 10% on all sales over 10,000.

Consider his last month sales is 38,000.

To find:

The total commission.

Solution:

4% commission on the first 10,000 of monthly sales is

$10,000\dfrac{4}{100}=400$

Sales over 10,000 is

$38,000-10,000=28,000$

10% commission on all sales over 10,000 is

$28,000\times \dfrac{10}{100}=2,800$

Now, the total commission is

$400+2,800=3,200$

Therefore, the total commission is 3,200.

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2 years ago

Can you please help me please please help

Triss [41]

Answer:

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2 years ago

A recipe states that 5 servings of peanuts have 1,250 calories. How many servings is 375 calories of peanuts? *

inysia [295]

1,250/5 = 250 calories per serving
375/250 = 1.5 servings

6 0

2 years ago

Read 2 more answers

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

1 year ago

Please bro- i cant do it...

beks73 [17]

Answer:

what

Step-by-step explanation:

u cant do what???,

8 0

2 years ago

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