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pashok25 [27]
4 years ago
10

Identify the branch of chemistry. percentage purity of glucose.

Chemistry
1 answer:
inna [77]4 years ago
4 0
Analytic chemistry

I think
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Gnoma [55]
In rivers or in mines
6 0
3 years ago
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Plz Help Me
Rasek [7]

Answer:- The wavelength is 1.36*10^1^2m and the right option is D.

Solution:-  Wavelength is inversely proportional to the frequency and the equation is:

\lambda =\frac{c}{\nu }

where, \lambda
 is the wavelength, c is the speed of light and \nu is frequency.

Frequency is 2.20*10^-^4Hz and the speed of light is 3.00*10^8\frac{m}{s} .

Since, 1Hz=1s^-^1

So, 2.20*10^-^4Hz=2.20*10^-^4s^-^1

Let's plug in the values in the equation:

\lambda =\frac{3.00*10^8m.s^-^1}{2.20*10^-^4s^-^1}

\lambda =1.36*10^1^2m

Hence, the right option is D) 1.36*10^1^2m .





7 0
3 years ago
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A flower has 26 chromosomes. To create a new flower how many chromosomes would a sperm cell have, what is this process called 2
enot [183]

Answer:

13 chromosomes, meiosis

Explanation:

the sperm cell contributes half of the chromosome in an offspring while the egg cells contributes the other half. Hence, the sperm cell has half of 26, 13. This process is called meiosis. Meiosis is when one cell undergoes cell division twice, thus creating 4 new cells. Each of these 4 new cells have half the amount of chromosomes as the original cell.

3 0
3 years ago
4
TiliK225 [7]
Given : Density of Bromine = 3.12 g/mL
Formula : Density = Mass / Volume

Part A :
Given Volume = 125 mL
Density = Mass / Volume
So, Mass = Density x Volume
= 3.12 x 125
= 390 grams

Part B :
Given mass = 85.0 gm
Density = Mass / Volume
So, Volume = Mass / Density
= 85 / 3.12
= 27.24 mL
8 0
4 years ago
Read 2 more answers
Consider the following reaction at 298K.
lakkis [162]

The true statements are;

  • K < 0
  • Eocel  < 0

<h3>What is a redox reaction?</h3>

We define a redox reaction as one in which a specie is oxidized and another is reduced.

Now;

Eo cell = cell potential = -0.13 V - (+0.34 V) = -0.47 V

n =number of moles of electrons = 2 mole of electrons

K = equilibrium constant

ΔG = change in free energy

Eo cell = 0.0592/n log K

-0.47 =  0.0592/2 log K

log K =  -0.47  * 2/0.0592

K = 1.3 * 10^-16

ΔG = -nFEo cell

ΔG = -(2 * 96500 * -0.47)

ΔG = 90.7kJ

Learn more about Ecell:brainly.com/question/10203847

#SPJ1

8 0
2 years ago
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