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musickatia [10]
4 years ago
13

Plz Help Me

Chemistry
2 answers:
telo118 [61]4 years ago
8 0

The answer is D.) 1.36 x 1012 m

Rasek [7]4 years ago
7 0

Answer:- The wavelength is 1.36*10^1^2m and the right option is D.

Solution:-  Wavelength is inversely proportional to the frequency and the equation is:

\lambda =\frac{c}{\nu }

where, \lambda
 is the wavelength, c is the speed of light and \nu is frequency.

Frequency is 2.20*10^-^4Hz and the speed of light is 3.00*10^8\frac{m}{s} .

Since, 1Hz=1s^-^1

So, 2.20*10^-^4Hz=2.20*10^-^4s^-^1

Let's plug in the values in the equation:

\lambda =\frac{3.00*10^8m.s^-^1}{2.20*10^-^4s^-^1}

\lambda =1.36*10^1^2m

Hence, the right option is D) 1.36*10^1^2m .





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Many of the lunar craters are due to volcanic eruptions true or false
elena-14-01-66 [18.8K]

Answer:

false

Explanation:

Craters on the Moon are caused by asteroids and meteorites colliding with the lunar surface. The Moon's surface is covered with thousands of craters. ... It also has very little geologic activity (like volcanoes) or weathering (from wind or rain) so craters remain intact from billions of years.

3 0
3 years ago
A mixture of NaBrO 3 , NaBrO3, NaHCO 3 , NaHCO3, Na 2 CO 3 , Na2CO3, and NaBr NaBr was heated, producing H 2 O , H2O, CO 2 , CO2
nata0808 [166]

Answer:

Composition of initial mixture is:

9.02g of NaBrO₃

15.84g of  Na₂CO₃

17.06g of NaHCO₃

82.58g NaBr

Explanation:

For the reactions:

2NaBrO₃(s) ⟶ 2NaBr(s) + 3O₂(g)

2NaHCO₃(s) ⟶ Na₂O(s) + H₂O(g) + 2CO₂(g)

Na₂CO₃(s) ⟶ Na₂O(s)+CO₂(g)

All H₂O(g) comes from NaHCO₃. Thus, initial moles and mass of NaHCO₃ are:

1.83g H₂O ₓ (1 mol H₂O / 18.02g) ₓ (2 mol NaHCO₃ / 1 mol H₂O) = <em>0.203moles NaHCO₃</em> ₓ (84g / 1mol NaHCO₃) =

<em>17.06g of NaHCO₃</em>

CO₂ comes from NaHCO₃ and Na₂CO₃.

15.51g of CO₂ are:

15.51g CO₂ ₓ (1mol / 44.01g) =<em> 0.352moles of CO₂</em>

As 2 moles of NaHCO₃ produce 2 moles of CO₂, moles of CO₂ that comes from NaHCO₃ are 0.203moles NaHCO₃. Moles of CO₂ that comes from Na₂CO₃ are:

0.352mol CO₂ - 0.203mol CO₂ = <em>0.149mol CO₂</em>

<em />

These moles of CO₂ are produced from:

0.149mol CO₂ ₓ (1 mol Na₂CO₃ / 1 mol CO₂) ₓ (106g / 1mol Na₂CO₃) =

<em>15.84g of  </em>Na₂CO₃

And all O₂ comes from NaBrO₃. Initial mass of NaBrO₃ is:

2.87g O₂ ₓ (1 mol O₂ / 32g) ₓ (2 mol NaBrO₃ / 3 mol O₂) ₓ (150.9g / 1mol NaBrO₃) =

<em>9.02g of </em>NaBrO₃

If initial mass of the mixture was 124.5g, mass of NaBr was:

124.5g - 9.02g of NaBrO₃ - 15.84g of  Na₂CO₃ - 17.06g of NaHCO₃ =

<em>82.58g NaBr</em>

<em />

<em>Composition of initial mixture is:</em>

<em>9.02g of NaBrO₃</em>

<em>15.84g of  Na₂CO₃</em>

<em>17.06g of NaHCO₃</em>

<em>82.58g NaBr</em>

5 0
4 years ago
Balance the following equation by inspection: <br> Cu + HNO3 --&gt; Cu(NO3)2 + H2O +NO
pashok25 [27]

Answer:

f is this

Explanation:

7 0
4 years ago
Read 2 more answers
Help me plzz and thank u
Gennadij [26K]

Answer:

the terminator because i did this test

5 0
3 years ago
What is the best description of what Becquerel observed in his experiment?
myrzilka [38]

The answer is: D.unstable nuclei emitting high-energy particles as they formed more stable compositions.

Those high-energy particles are alpha particles , beta particles , gamma radiation.

For example, the decay chain of ²³⁸U is called the uranium series.

Decay start with U-238 and ends with Pb-206. There are several alpha and beta minus decays.

Antoine Henri Becquerel (1852 – 1908) was a French physicist and the first person to discover evidence of radioactivity.

Becquerel wrapped fluorescing crystal (uranium salt potassium uranyl sulfate) in a cloth, along with the photographic plate and a copper Maltese cross.

Several days later, he discovered that a image of the cross appeared on the plate.

The uranium salt was emitting radiation.

Because of this discovery, Becquerel won a Nobel Prize for Physics in 1903, which he shared with Marie Curie and Pierre Curie.


5 0
3 years ago
Read 2 more answers
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