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nadya68 [22]
2 years ago
10

Need help with chemistry problem

Chemistry
1 answer:
sukhopar [10]2 years ago
6 0

Answer:

b option sir sidd dichhi good book goo

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1) If the pressure on 2.6 liters of a gas at 860 Torr is increased to 1000 Torr,
LenKa [72]

2.24 liters is the volume of the gas if pressure is increased to 1000 Torr.

Explanation:

Data given:

Initial volume of the gas V1 = 2.6 liters

Initial pressure of the gas P1 = 860 Torr 1.13 atm

final pressure on the gas P2 = 1000 Torr 1.315 atm

final volume of the gas after pressure change V2 =?

From the data given above, the law used is :

Boyles Law equation:

P1V1 = P2V2

V2 = P1V1/P2

   = 1.13 X 2.6/ 1.31

  = 2.24 Liters

If the pressure is increased to 1000 Torr or 1.315 atm the volume changes to 2.24 liters. Initially the volume was 2.6 litres and the pressure was 860 torr.

6 0
3 years ago
Can you help please??
hram777 [196]

Answer:

no

Explanation:

7 0
2 years ago
Read 2 more answers
Which elements can form acidic compounds? sulfur
son4ous [18]

Answer:

Any element

Explanation:

Any element that produces an extra proton, aka a Hydrogen cation, or H⁺

3 0
2 years ago
What elements start with Ne
tatyana61 [14]
The element that starts with Ne is Neon.
3 0
3 years ago
Volume of a gas at STP, if its volume is 80.0 mL at 1.08 atm and –12.5oC.
vodomira [7]

Answer:

90.5mL is the volume of the gas at STP

Explanation:

It is possible to find volume of a gas when conditions of temperature and pressure change using combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Where P is pressure, V is volume and T is absolute temperature. 1 is initial conditions and 2 final conditions.

If initial conditions are 1.08atm, 80.0mL and absolute temperature is (-12.5°C + 273.15) = 260.65K.

And STP are 1atm of pressure and 273.15K of absolute temperature. Replacing:

\frac{1.08atm80.0mL}{260.65K} =\frac{1atmV_2}{273.15K}

V₂ = <em>90.5mL is the volume of the gas at STP</em>

7 0
2 years ago
Read 2 more answers
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