When there is a negative charge on an atom then we add the charge with the number of electrons. Whereas when there is a positive charge on an atom then we subtract the charge from the number of electrons.

Atomic number of chlorine is 17. So, number of electrons present in $Cl^{-}$ is 17 + 1 = 18 electrons.

Atomic number of cobalt is 27. So, number of electrons present in $Co^{4+}$ is 27 - 4 = 23 electrons.

Atomic number of iron is 26. So, number of electrons present in $Fe^{2+}$ is 26 - 2 = 24 electrons.

Atomic number of vanadium is 23. So, number of electrons present in V is 23 electrons.

Atomic number of scandium is 21. So, number of electrons present in $Sc^{2-}$ is 21 + 2 = 23 electrons.

Thus, we can conclude that out of the given species, $Fe^{2+}$ has the greatest number of electrons.

4 0

4 years ago

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Copper (II) nitrate, Cu(NO3)2, solution reacts with potassium hydroxide, KOH, to form a blue

Gekata [30.6K]

Answer:

Copper(II) nitrate and potassium hydroxide are soluble ionic compounds, which implies that they dissociate completely when dissolved in water to produce ions. ... You can thus say that the balanced chemical equation that describes this double ... Cu(NO3)2(aq)+2KOH(aq)→Cu(OH)2(s)⏐⏐↓+2KNO3(aq).

6 0

3 years ago