Answer:

Step-by-step explanation:
So we need to find an equation of a line that crosses the point (6,-4) and is perpendicular to y = -2x -3.
First, let's find the slope of the line we want to write. The line we want is perpendicular to y = -2x -3. Recall that if two lines are perpendicular to each other, their slopes are negative reciprocals of each other. What this means is that:

Plug -2 for one of the slopes.

Divide by -2 to find the slope of our line.

Thus, our line needs to have a slope of 1/2.
Now, let's use the point-slope form. The point-slope form is given by:

Plug in 1/2 for the slope m and let's let our point (6,-4) be x₁ and y₁. Thus:

Simplify and distribute:

Subtract 4 from both sides:

The above is the equation that passes the point (6,-4) and is perpendicular to y = -2x -3.
The answer is c
I love math btw
A = -0.7
B = -9/16 (0.5623)
C = -0.4
D = -5/16 (0.3125)
The last option is correct
I believe the answer is 8
Answer:
Sorry to waist your time but no one would know this not even the person who made the question.
Step-by-step explanation: