Question

The gas in a cylinder has a volume of 5 liters at a pressure of 115 kPa. The pressure of the gas is increased to 211 kPa. Assuming the temperature remains constant, what would the new volume be?

Answer 1

We know the initial pressure and volume, the final pressure, and the temperature is constant, Using the G.U.E.S.S. method we can express the problem like this:                                             
$Givens: V_1=5 L, P_1= 115kPa, P_2= 211kPa$
$Unknown: V_2$ 
$Equation: \frac{V_1P_1}{P_2}=V_2$
$Substitute: \frac{5L*115kPa}{211kPa}= V_2$
$Solve: \frac{5L*115kPa}{211kPa}= 2.73 or 2.72L$

      In conclusion, your answer is either 2.73 kPa if you round or 2.72 kPa if you don't. Hope you learned from it.