Explanation:
There are 5 kinematic equations, and 5 variables.
Each question will give you 3 variables and ask you to solve for a fourth.
To determine which equation to use, look at which variable is <em>not</em> included in the problem.
For example, if the question does not include time, then you need to use a kinematic equation that does not have t in it. That would be:
v² = v₀² + 2aΔx
Or, if the question does not include the final velocity, then you need a kinematic equation that does not have v in it. That would be:
Δx = v₀ t + ½ at²
Answer:
His average speed is 0.15 kilometer per minute or 2.5 meters per second.
Explanation:
average speed = distance/time
x = 3 km/20 minutes
x = 0.15
—
x = 3000 m/1200 s
x = 2.5
If you look up "distance vs time graph" you can pull up images on google and check them out. That's what I did and on the x-axis (horizontal line) it said "time." I'd go with time.
To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)
To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)
To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)
To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)
Answer:
a)0.024
b)0.148
Explanation:
Let 's represent the set of deer ticks Carrying Lyme disease with L and the set of deer ticks carrying Human Granulocytic Ehrlichiosis with H
Given:
P(L) = 0.16
P(H) = 0.10
P(L n H) = 0.1 ·P( L u H )
Hence, P( L u H) = 10 ·P( L nH)
(a)
Hence. using the equation. P(L U H) = P(L) + P(H) - P(L n H)
Hence, 10 · P(L n H ) = 0.16 + 0.1 - P(L n H )
Hence, 11 · P(L n H) = 0.16 + 0.1 = 0.26
Hence, P(L n H) =
0.26/11=0.024
(b)
We know that condition probability P(H ║ L) = p(L n H)/P(L)
hence, P(H ║ L) =(0.26/11)/0.16 =0.148
