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3 years ago

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Objects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the charge of Object 1 is doubled AND the distan

ce separating Objects 1 and 2 is tripled, then the new electrostatic force will be _____ units

1 answer:

melamori03 [73]3 years ago

6 0

Answer:

8 units

Explanation:

F=(k*q1*q2)/(r^2)

K is a constant, q1 is charge of 1, q2 is charge of 2, r is distance between the two.

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Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3

solong [7]

Answer:

v = 5.166 10² m / s

Explanation:

We can solve this exercise using the kinematics equations

v = v₀ + at

as the bullet starts from rest its initial velocity is zero

v = a t

let's calculate

v = 6.3 10⁵ 8.2 10⁻⁴

v = 5.166 10² m / s

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2 years ago

A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-

Alisiya [41]

First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
$1 rev= 2 \pi rad$
$1 min = 60 s$
the angular speed is
$\omega = 7.18 \frac{rev}{min} \cdot \frac{2 \pi}{60} = 0.75 rad/s$

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
$v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s$

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3 years ago

My dog Ubu can run at 21 mi/h. How far can he travel in 40 minutes?

Anna007 [38]

Answer:

14

Explanation:

21miles/3=7

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3 years ago

The resultant of 2 forces at right angles is 100 lbs. If one of the forces makes an angle of 30 degress with the resultant, comp

Ipatiy [6.2K]

Answer:

86.6 lbs

Explanation:

Let the force is X.

Resultant force, R = 100 lbs

Other force is Y. Angle between resultant force and force X is 30°.

According to the diagram

$Cos30=\frac{X}{R}$

$0.866=\frac{X}{100}$

X = 86.6 lbs

Other force Y

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$0.5=\frac{Y}{100}$

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3 years ago

A ball has an electric charge of +1.5 × 10-9 coulombs. At what distance from the ball's center is the electric field strength eq

Veronika [31]

F = kq1q2/r<span>2
Where,
F - Coulomb Force
k - constant value which is equal to </span>8.98 × 10^9<span> newton square metre per square coulomb
q1 and q2 - two electric charges
r - distance.

5.8 * 10^5 = 1.5 * 10^-9 / r^2
</span><span>5.8 * 10^5 r^2 = 1.5*10^-9
</span>r^2 = 0.0000258620
r = 0.0050854694

So the distance is equal to 5.09 x 10^-3

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3 years ago