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3 years ago

In a circuit a battery is used to

Physics

2 answers:

Anarel [89]3 years ago

7 0

Produce power through the circuit.

melisa1 [442]3 years ago

5 0

The power of batteries in a circuit. The key functions of a battery and bulb in a circuit are explained. A battery is a source of energy which provides a push - a voltage - of energy to get the current flowing in a circuit. A bulb uses the electrical energy provided by the battery, but does not use current.

HOPE IT HELPS YOU OUT

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The charge of an electron is -1.60x10-19 C. A current of 1 A flows in a wire carried by electrons. How many electrons pass throu

faltersainse [42]

Answer: $6.241\times 10^{18}$ electrons pass through a cross section of the wire each second.

Explanation:

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

Given : Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C$

To calculate the charge passed we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 1 A

q = total charge = ?

t = time required = 1 sec

Putting values in above equation, we get:

$1A=\frac{q}{1s}\\\\q=1A\times 1s=1C$

When 96500C of electricity is passed , the electrons passed = $6.022\times 10^{23}$

1 C of electricity is passed , the electrons passed = $\frac{6.022\times 10^{23}}{96500}\times 1C=6.241\times 10^{18}$

Hence, $6.241\times 10^{18}$ electrons pass through a cross section of the wire each second.

4 0

3 years ago

A ship tows a submerged cylinder, which is 1.5 m in diameter and 22 m long, at 5 m/s in fresh water at 208C. Estimate the towing

Scilla [17]

Answer: a) P = 120kw

b) P = 800kw

Explanation: Please find the attached file for the solution

8 0

3 years ago

Read 2 more answers

A car drives on a circular road of radius R. The distance driven by the car is given by = + [where a and b are constants, and t

pishuonlain [190]

Answer:

The question is incomplete, the complete question is "A car drives on a circular road of radius R. The distance driven by the car is given by d(t)= at^3+bt [where a and b are constants, and t in seconds will give d in meters]. In terms of a, b, and R, and when t = 3 seconds, find an expression for the magnitudes of (i) the tangential acceleration aTAN, and (ii) the radial acceleration aRAD3"

answers:

a. $18a m/s^{2}$

b. $a_{rad}=\frac{(27a +b)^{2}}{R}$

Explanation:

First let state the mathematical expression for the tangential acceleration and the radial acceleration.

a. tangential acceleration is express as

$a_{tan}=\frac{d|v|}{dt} \\$

since the distance is expressed as

$d=at^{3}+bt$

the derivative is the velocity, hence

$V(t)=\frac{dd(t)}{dt}\\V(t)=3at^{2}+b\\$

hence when we take the drivative of the velocity we arrive at

$a_{tan}=\frac{dv(t)}{dt}\\ a_{tan}=6at\\t=3 \\we have \\a_{tan}=18a m/s^2$

b. the expression for the radial acceleration is expressed as

$a_{rad}=\frac{v^{2}}{r}\\a_{rad}=\frac{(3at^{2} +b)^{2}}{R}\\t=3\\a_{rad}=\frac{(27a +b)^{2}}{R}$

4 0

2 years ago

What is the magnitude of vector K ?

vovangra [49]

Answer:

Vector K = 8 m

Explanation:

The given figure shows a right angle triangle JKL. It is given that :

vector L = 10 m

vector J = 6 m

We have to find vector k. We can find it by using Pythagoras theorem. According to this theorem, the sum of squares of perpendicular and the base is equal to the square of the longest side.

$L^2=K^2+J^2$

$K^2=L^2-J^2$

$K^2=(100)^2-(6)^2$

K = 8 m

Hence, the magnitude of vector K is 8 m.

3 0

2 years ago

T Object]User: Which of the following does not affect the electrical resistance of a body?

exis [7]

Material composing the body, temperature of the body and the length of the body affects the electrical resistance of a body. Bodies directly surrounding the body will not affect the electrical resistance of the body. The answer is letter D.

4 0

3 years ago

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