For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as
Wt=1945.475J
<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>
Generally, the equation for work is mathematically given as
Wt=wac+Wc+Wba
Therefore
Wac=Pa(Vc-Va)=nR(Tc-Ta)
Wac=3(8.314*192)
Wac=4788.864J
Wcb=P1v1-p2v2/v-1
Wcb-3*8.34*108/0.4
Wcb=-6734.34J
Wab=0
In conclusion,
Wt=wac+Wc+Wba
Wt=4788.864J+0+(-6734.34J)
Wt=+1945.475J
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<u>Given data</u>
Determine Internal energy of gas N₂, (U) = ?
Temperature (T) = 25° C
= 25+273 = 298 K,
Gas constant (R) = 8.31 J/ mol-K ,
Number of moles (n) = 3 moles,
<u>Internal energy of N₂ </u>
Internal energy is a property of thermodynamics, the concept of internal energy can be understand by ideal gas. For example N₂, the observations for oxygen and nitrogen at atmospheric temperatures, f=5, (where f is translational degrees of freedom).
So per kilogram of gas,
The internal energy (U) = 5/2 .n.R.T
= (5/2) × 3 × 8.31 ×298
= 18572.85 J
<em>The internal energy of the N₂ is 18,572.85 J and it is approximately equal to 18,600 J given in the option B.</em>
Answer:
Therefore the horizontal range = 294897.96 m.
Explanation:
Range of a projectile: The range is defined as the horizontal distance from the point of projection to the point where the projectile hit the projection plane again. The S.I unit of range is Meter (m).
It can be expressed mathematically as
R = u²sin2∅/g............................. Equation 1
Where R = Horizontal range, ∅ = angle of projection, u = initial velocity, g = acceleration due to gravity.
<em>Given: u = 1700 m/s, </em>∅ = 55°,
Constant: g = 9.8 m/s²
Substituting these values into equation 1
R = (1700²sin55)/9.8
R = 2890000/9.8
R = 294897.96 m.
Therefore the horizontal range = 294897.96 m.
If an element has a charge of +1, there is 1 more proton than electrons.
A proton has a charge of +1
A neutron has a charge of 0
A electron has a charge of -1.
For there to be a charge of 0, there would be the same amount of charges for both proton and neutron. To get a charge of 1, you will need 1 more proton.
hope this helps
