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dem82 [27]
3 years ago
10

A family ordered some candy bars and bags of chips for snacking. The number oof candy bars was twice as much as the number of ba

gs of chips. If the family spent a total of %5.50, how many bags of chips did the family buy?
Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0

Answer:

The family bought 2 bags of chips

Step-by-step explanation:

Let the number of chips bags be  =   x

The number of candy bars  =  twice as much as the number of bags of chip

The number of candy bars  =  2x

The total cost  spent is  = $5.50

Therefore cost of all the chips bags + candy bars = 5.50

2x +  x = 5.50

3x = 5.50

x = \frac{5.50}{3}

x =  1.83

x = 2 (approx)

Thus the number of chips is 2 and the candy bars is 2(2) = 4 bags

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