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wel
4 years ago
15

An example of an object making a revolution

Physics
1 answer:
ICE Princess25 [194]4 years ago
5 0

Earth

Electrons in orbit

Explanation:

Revolution is the movement of an object along an orbit.

It implies the movement of an object round another one.

  • Rotation is the movement of an object on its own fixed axis.

The movement of earth along an orbit round the sun is a revolution. The earth is moving and sweeping past elliptical orbits.

Electrons in orbits round the nucleus are also revolving.

They are moving along orbits defined by their own energy level.

  • A fan blade is rotating because is fixed to a center.
  • A case player also rotates.

The earth also rotates on its axis.

learn more:

Rotation and transformation brainly.com/question/3779181

#learnwithBrainly

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A point charge of magnitude q is at the center of a cube with sides of length L.a) What is the electric flux through each of the
agasfer [191]
<h2>The flux through each face is q/6ε₀ .</h2>

Explanation:

The charge q is placed at the center of the cube of side L

According to Gauss's law the flux through any closed surface is q/ε₀

here q is the charge enclosed .

In this case cube has the six faces . The flux through each face = q/6ε₀

In the second case The cube has the face with length L₁

The flux through each face = q/6ε₀

Thus flux through the cube does not depend upon the size of the cube .

3 0
3 years ago
On a cold day, a heat pump absorbs heat from the outside air at 14°F (−10°C) and transfers it into a home at a temperature of 86
Art [367]

Answer:

6.575

Explanation:

T1 = 30C = 30 + 273 = 303 K

T2 = - 10 C = - 10 + 273 = 263 K

The coefficient of performance of heat pump

k = T2 / (T1 - T2)

k = 263 / (303 - 263) = 6.575

4 0
3 years ago
Horizontal rows are called ( )<br> and represent ( ) levels. <br> () are why I need answers plz
Rudiy27

Answer:

1. Periods; that are what horizontal rows on a periodic table are called.

2. Each period represents the number of levels

Explanation:

3 0
4 years ago
A stack of 1500 bricks covers a ground area of 2.750m by 1.350m.the average mass of bricks is 3.200kg.calculate the total force
lozanna [386]

The total force on the ground due to the bricks is 47,040 N.

<h3>Total force on the ground</h3>

The total force on the ground due to weight of the bricks is calculated as follows;

Fₙ = mg

where;

  • Fₙ is normal force
  • m is mass of the brickes
  • g is acceleration due to gravity

Fₙ = (1500 x 3.2) x 9.8

Fₙ = 47,040 N

Thus, the total force on the ground due to the bricks is 47,040 N.

Learn more about total force here: brainly.com/question/14361879

#SPJ1

5 0
2 years ago
An Atwood machine is constructed using a
Nesterboy [21]

Answer:

a=1.03 m/s²

Explanation:

given                                  required

dist=22.1 cm                    a=?

m1=2.1 kg

m2=1.56 kg

m3=1.93 kg

g=9.8 m/s²

solution

there are three forces on this system so we can solve by using newton's second law as follows

t1,t2,and weight of are the only forces acted on the system,

if we take the system on the left mass m3

-m3a=t2-m3g

-1.93 kg×a=t2-1.93 kg×9.8 m/s²

-1.93 kg×a=t2-18.91 N................................ eq 1

take at the right mass m2

m2a=t2-m2×g

1.56 kg×a=t2-1.56 kg×9.8 m/s²

1.56 kg×a=t2-15.288 N...................................2

add the two equations simultaneously and then solve for a,

-1×(-1.93 kg×a=t2-18.91 N) multiply by -1 the first and add the two equations

1.56 kg×a=t2-15.288 N

3.49 kg×a=3.622 N

a=1.03 m/s²

3 0
4 years ago
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