Answer:
a=1.03 m/s²
Explanation:
given required
dist=22.1 cm a=?
m1=2.1 kg
m2=1.56 kg
m3=1.93 kg
g=9.8 m/s²
solution
there are three forces on this system so we can solve by using newton's second law as follows
t1,t2,and weight of are the only forces acted on the system,
if we take the system on the left mass m3
-m3a=t2-m3g
-1.93 kg×a=t2-1.93 kg×9.8 m/s²
-1.93 kg×a=t2-18.91 N................................ eq 1
take at the right mass m2
m2a=t2-m2×g
1.56 kg×a=t2-1.56 kg×9.8 m/s²
1.56 kg×a=t2-15.288 N...................................2
add the two equations simultaneously and then solve for a,
-1×(-1.93 kg×a=t2-18.91 N) multiply by -1 the first and add the two equations
1.56 kg×a=t2-15.288 N
3.49 kg×a=3.622 N
a=1.03 m/s²
