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Kamila [148]
3 years ago
6

A ball is dropped from the top of an eleven-story building to a balcony on the ninth floor. In which case is the change in the p

otential energy associated with the motion of the ball the greatest
Physics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

at the top of the 9 story building i think

Explanation:

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ruslelena [56]

a plasma is a hot ionized gas consisting of equal numbers and positively charged ions and negativly charged electrons. the characterisitcs of plasma are different from those of oirdinary gases so plama is consideres the fourth state of matter

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3 years ago
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A 0.060-kg tennis ball, moving with a speed of 5.50m/s , has a head-on collision with a 0.090-kg ball initially moving in the sa
Yuliya22 [10]

Answer:

Explanation:

For elastic collision , the formula for velocity of .06 kg  is

v₁ = (m₁-m₂)/(m₁+m₂) u₁ + 2m₁m₂/(m₁+m₂) u₂

=( .06-.09 / .06+.09 ) 5.5 + (2 x .06 x .09 / .06+.09 ) 3.4

=( -.03 / .15) x 5.5 + (2 x .0054 / .15) x 3.4

= -1.1 +.2448

= - 0 .8552 m/s

Its direction will be - opposite direction

the formula for velocity of .09kg  is

v₂ = (m₂-m₁)/(m₁+m₂) u₂ + 2m₁m₂/(m₁+m₂) u₁

= ( .09-.06 / .06+.09 ) 3.4 + (2 x .06 x .09 / .06+.09 ) 5.5

= .68 +.396

= 1.076 m / s

Its direction will be in the same direction .

4 0
4 years ago
An earthquake creates a type of wave that shakes the ground. If a large earthquake occurs in Greece, how can the waves be felt a
Cloud [144]
The sound waves travel through the sea which creates movement which can be felt all the way in Italy in the sea- like a domino effect
7 0
3 years ago
A planet has been observed orbiting a nearby star. This star has a mass of 3.5 solar masses, and the planet is 4.2 AU from the s
kondaur [170]

Answer:

4.6 years

Explanation:

This is solved using Kepler's third law which says:

T^2=\frac{4\pi ^2}{GM} a^2

Where

T = Orbital period of the planet (in seconds)

a = Distance from the star (in meters)

G = Gravitational constant

M = Mass of the parent star (in kg)

From the information given

M = 3.5M_{sun} = 6.96*10^{30} kg

a=4.2AU = 6.28*10^{11} meters

G = 6.67*10^{-11}m^3kg^{-1}s^{-2}

We put this into Kepler's law and get:

T=\sqrt{\frac{4\pi ^2}{6.67*10^{-11}*6.96*10^{30}} (6.28*10^{11})^3}=145,128,196 seconds.

This when converted to years is 4.6 years.

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3 years ago
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The answer is a pendulum swings back an forth.
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