The approach of critical value is used to determine likely or unlikely through determination whether observed test statistics is more than it would have been if null hypothesis was true. In other words, test statistics is compared to critical value and decision made.
If test statistics is more than critical value, the null hypothesis is rejected. Otherwise, null hypothesis is not rejected.
In the current scenario, test statistics (2.148) is less than critical value (2.348) and thus null hypothesis is not rejected.
Answer: then study its easy
Step-by-step explanation: first you open your book and you read over everything that will be on the test. and then u wont fail bih
Answer:
C 200
Step-by-step explanation:
It does not appear to be LINEAR so
Start with :
pulse rate = y = 73e^kx
sub in x = .7 when y = 155
155 = 73 e^(.7 * k)
ln ( 155/73) = .7k
.75296567 = .7k
k = 1.07567
for x = 0.9 :
pulse rate = y = 73 e^(1.07567 * .9) = ~ 192 so I expect answer is 200
I
tan(32)x21=13mm
j
7.32/cos(66)=17.9cm
k
tan(34)x26.8=18m
i
23.9/tan(49)=20.7km
:)Good luck in Math
Answer:
d
Step-by-step explanation:
d. neither
If I helped please vote brainliest
