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Marizza181 [45]
2 years ago
14

How do I find the percent of budget?​

Mathematics
1 answer:
ch4aika [34]2 years ago
6 0

Answer:

First, subtract the budgeted amount from the actual expense. If this expense was over budget, then the result will be positive.

Next, divide that number by the original budgeted amount and then multiply the result by 100 to get the percentage over budget. If your expenses were lower than your budgeted amount, then this number will be negative, describing the percentage under budget.

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What is the least common denominator of the fraction 3 x over x plus 1 plus the fraction x plus 1 over 2 x plus the fraction 5 o
Hoochie [10]
3x/(x+1) + (x+1)/(2x) + (5/x)

To find the least common denominator, we multiply the denominators that cannot factor into eachother. x, the denominator in 5/x, fits into 2x, so we do not need to multiply this number.
Therefore, the least common denominator is:
2x(x+1) 

The first term will be multiplied by 2x/2x
The second term will be multiplied by (x+1)/(x+1)
The third term will be multiplied by 2(x+1)
3 0
3 years ago
Help me out with these please!<br><br> No links to suspicious sites!
weeeeeb [17]

Answer:

1) N = 2. 2) -7/3

Step-by-step explanation:

1)

6 = 3n

6/3 = n

2 = n

n = 2

2)

-3 = 3t + 4

3t + 4 = -3

3t = -3 - 4

3t = -7

T = -7/3

5 0
3 years ago
Read 2 more answers
Two less than the quotient of a number and 5
atroni [7]
N/5 - 2 is the answer 
4 0
3 years ago
Solve the following system of equations. What is one x-value of a solution?
gulaghasi [49]

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}

x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}

x = \frac{-36 \pm 33.11}{2}

x_1 = \frac{-36 + 33.11}{2}

x_1 = -1.445

x_2 = \frac{-36 - 33.11}{2}

x_2 = -34.555

5 0
3 years ago
How do you do this trig problem.
loris [4]

Consider a right triangle in which one of the angles \theta satisfies

\sin\theta=\dfrac35\implies\theta=\sin^{-1}\dfrac35

That is, the side opposite \theta occurs in a ratio of 3 to 5 with the hypotenuse. The side adjacent to \theta then occurs in a ratio of 4 to 5 with the hypotenuse. In other words,

\cos\theta=\dfrac45

because

\sin^2\theta+\cos^2\theta=\dfrac9{25}+\dfrac{16}{25}=1

Then in this triangle,

\cot\theta=\cot\left(\sin^{-1}\dfrac35\right)=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac45}{\frac35}=\dfrac43

7 0
2 years ago
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