Answer:
a. <u>2</u> MnO₄⁻ (aq) +<u>3 </u>C₂O₄²⁻(aq) +
b. <u>0</u> H⁺(aq) + <u>4</u>OH⁻ (aq) +
c. <u>0</u> H₂O(l) → 2 MnO₂(s) +
d. <u>6</u>CO₃²⁻(aq) + <u>0</u> H⁺(aq) +
e. <u>0</u> OH⁻(aq) + <u>2</u>H₂O(l)
Explanation:
At first you write skeleton chemical equation and then balanced by using ion electron method
Permanagante ion reacts in basic medium by the following
MnO₄⁻ + 2H₂O +3e⁻ → MnO₂ + 4 OH⁻ ......................(i)
MnO₄⁻ acts as a oxidising agent which oxidised oxalate ion into carbonate ion and reduced itself into solid MnO₂.
C₂O₄²⁻ + 4 OH⁻ → 2 CO₃²⁻ + 2e⁻ + 2H₂O .....................(ii)
Multiplying equation (i) by factor 2 and equation (ii) by factor 3
rewrite the equation
2 MnO₄⁻ + 4 H₂O +6 e⁻ → 2 MnO₂ + 8 OH⁻---------------------------(iii)
3 C₂O₄²⁻ + 12 OH⁻ → 6 CO₃²⁻ + 6 e⁻ + 6 H₂O-----------------------(iv)
Noe add the equation (iii) + (iv)
we get 2 MnO₄⁻ + 3 C₂O₄²⁻ + 4 OH⁻ → 6 CO₃²⁻ + 2 MnO₂ + 2 H₂O