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Archy [21]
3 years ago
9

Positrons are spontaneously emitted from the nuclei of

Chemistry
2 answers:
Fudgin [204]3 years ago
6 0

Answer: Option (1) is the correct answer.

Explanation:

  • A positron is a small particle which contains a +1 charge and its mass is equal to the mass of an electron, that is, 9.109 \times 10^{-31} kg.

A positron is represent by the symbol ^{0}_{+1}\beta.

For example, ^{37}_{19}K \rightarrow ^{37}_{18}Ar + ^{0}_{+1}\beta

  • Whereas nitrogen-16 does not decay to give a positron because nitrogen-16 is the daughter isotope formed due to decay of oxygen-16.

The decay reaction is as follows.

           ^{16}_{8}O \rightarrow ^{16}_{7}N + ^{0}_{+1}\beta

  • And, on radioactive decay of thorium-232 there will be formation of radium-228 along with emission of an alpha particle.

The reaction will be as follows.

            ^{232}_{90}Th \rightarrow ^{228}_{88}Ra + ^{4}_{2}\alpha

Therefore, we can conclude that out of the given options positrons are spontaneously emitted from the nuclei of potassium-37.

Leto [7]3 years ago
4 0
Positrons are spontaneously emitted from the nuclei of potassium -37.
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Oxygen gas generated in an experiment is collected at 25.0°C in a bottle inverted in a trough of water. The total pressure is 1.
Nitella [24]

Answer:

0.007 mol

Explanation:

We can solve this problem using the ideal gas law:

PV = nRT

where P is the total pressure, V is the volume, R the gas constant, T is the temperature and n is the number of moles we are seeking.

Keep in mind that when  we collect a gas over water we have to correct for the vapor pressure of water at  the temperature in the experiment.

Ptotal = PH₂O + PO₂  ⇒ PO₂ = Ptotal - PH₂O

Since R constant has unit of Latm/Kmol we have to convert to the proper unit the volume and temperature.

P H₂O = 23.8 mmHg x 1 atm/760 mmHg =  0.031 atm

V = 1750 mL x 1 L/ 1000 mL = 0.175 L

T = (25 + 273) K = 298 K

PO₂ = 1 atm - 0.031 atm = 0.969 atm

n =  PV/RT = 0.969 atm x  0.1750 L / (0.08205 Latm/Kmol x 298 K)

n = 0.007 mol

6 0
3 years ago
Boiling and melting points exploration<br>​
juin [17]

Answer:

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Explanation:

6 0
3 years ago
The specific heat of copper is 0.093 cal/g0C. Calculate the temperature change that occurs if 28 g of copper at 25 0C absorbs 58
Umnica [9.8K]

Answer:

22.27 °C = ΔT

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m × c × ΔT

Given data:

mass = 28 g

heat absorbed = 58 cal

specific heat of copper =  0.093 cal/g .°C

temperature change =ΔT= ?

Solution:

Q = m × c × ΔT

58 cal = 28 g × 0.093 cal /g.°C × ΔT

58 cal = 2.604 cal.°C × ΔT

58 cal / 2.604 cal .°C = ΔT

22.27 °C = ΔT

5 0
3 years ago
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Answer:

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Explanation:

hope it helps...i dont know if its right but i hope it helps

3 0
3 years ago
Where is greatest amount of fresh water in the world found? A. wetlands B. rivers C. glaciers D. lakes
WINSTONCH [101]

Answer:

C. Glaciers

Explanation:

Over 68 percent of the fresh water on Earth is found in icecaps and glaciers, and just over 30 percent is found in ground water. Only about 0.3 percent of our fresh water is found in the surface water of lakes, rivers, and swamps.

Hope this helps!

All the love, Ya boi Fraser :)

7 0
3 years ago
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