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Archy [21]
3 years ago
9

Positrons are spontaneously emitted from the nuclei of

Chemistry
2 answers:
Fudgin [204]3 years ago
6 0

Answer: Option (1) is the correct answer.

Explanation:

  • A positron is a small particle which contains a +1 charge and its mass is equal to the mass of an electron, that is, 9.109 \times 10^{-31} kg.

A positron is represent by the symbol ^{0}_{+1}\beta.

For example, ^{37}_{19}K \rightarrow ^{37}_{18}Ar + ^{0}_{+1}\beta

  • Whereas nitrogen-16 does not decay to give a positron because nitrogen-16 is the daughter isotope formed due to decay of oxygen-16.

The decay reaction is as follows.

           ^{16}_{8}O \rightarrow ^{16}_{7}N + ^{0}_{+1}\beta

  • And, on radioactive decay of thorium-232 there will be formation of radium-228 along with emission of an alpha particle.

The reaction will be as follows.

            ^{232}_{90}Th \rightarrow ^{228}_{88}Ra + ^{4}_{2}\alpha

Therefore, we can conclude that out of the given options positrons are spontaneously emitted from the nuclei of potassium-37.

Leto [7]3 years ago
4 0
Positrons are spontaneously emitted from the nuclei of potassium -37.
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How does the current model of the atom differ from j.j. thomsons model
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secondary consumer

The rabbits would be considered the primary consumer so that makes the coyote a secondary consumer.

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3 years ago
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A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co
KengaRu [80]
In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

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Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT                      PV
----    ------    --->    n = --------
 RT     RT                       RT

          10130.0 kPa  x 50 L
n= ---------------------------------------------
       8.314 L. kPa/K.mol  x 573.15 K
             506,500 
  =  ----------------------------
         4,765.17  mol K

=106.29 mol Ar

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