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Archy [21]
3 years ago
9

Positrons are spontaneously emitted from the nuclei of

Chemistry
2 answers:
Fudgin [204]3 years ago
6 0

Answer: Option (1) is the correct answer.

Explanation:

  • A positron is a small particle which contains a +1 charge and its mass is equal to the mass of an electron, that is, 9.109 \times 10^{-31} kg.

A positron is represent by the symbol ^{0}_{+1}\beta.

For example, ^{37}_{19}K \rightarrow ^{37}_{18}Ar + ^{0}_{+1}\beta

  • Whereas nitrogen-16 does not decay to give a positron because nitrogen-16 is the daughter isotope formed due to decay of oxygen-16.

The decay reaction is as follows.

           ^{16}_{8}O \rightarrow ^{16}_{7}N + ^{0}_{+1}\beta

  • And, on radioactive decay of thorium-232 there will be formation of radium-228 along with emission of an alpha particle.

The reaction will be as follows.

            ^{232}_{90}Th \rightarrow ^{228}_{88}Ra + ^{4}_{2}\alpha

Therefore, we can conclude that out of the given options positrons are spontaneously emitted from the nuclei of potassium-37.

Leto [7]3 years ago
4 0
Positrons are spontaneously emitted from the nuclei of potassium -37.
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Given AgBr(s) => Ag⁺(aq) + Br⁻(aq) ; Ksp = 5 x 10⁻¹³ = [Ag⁺][Br⁻]

    I       ---                0              0

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