Al + O2 = What product will complete the equation? PLS HELP

Solid iron metal reacts with solid sulfur at room temperature to produce solid iron (ll) sulfide? Express as a chemical equation

kupik [55]

Answer:Fe+S=FeS

Hope this helps

5 0

3 years ago

In a laboratory experiment, a student titrates 10.0 mL of acetic acid, CH3COOH, solution with 0.5 M NaOH. The endpoint was reach

Rzqust [24]

Answer:

Concentration of acetic acid=2.3mol/L

Explanation:

Write the balanced chemical reacion:

$CH_3COOH +NaOH = Na(CH_3COO) +H_2O$

N1 and N2 normality of CH3COOH and NaOH respectively;

V1 and V2 volume of CH3COOH and NaOH respectively and they are taken upto end point of titration;

we have given molarity but we need normality;

$Normality =molarity \times n-factor$

but in case of NaOH and CH3COOH n-factor is 1 for each.

hence

normality=molarity;

$N_1V_1=N_2V_2$

$N_1 \times 10 =0.5\times 46$

$N_1=2.3=molarity=concentration;$

Concentration of acetic acid=2.3mol/L

8 0

3 years ago

WHAT is the chemistry/chemical principle behind making SMOOTHIES??

givi [52]

the power of the blender allows the chemicals in the seperate foods to join togather

8 0

3 years ago

Consider the balanced equation.

vaieri [72.5K]

The balanced chemical reaction is:

N2 + 3H2 = 2NH3

We are given the amount of H2 being reacted. This will be our starting point.

26.3 g H2 (1 mol H2 / 2.02 g H2) 2 mol O2/3 mol H2) ( 17.04 g NH3 / 1mol NH3) = 147.90 g O2

Percent yield = actual yield / theoretical yield x 100

Percent yield = 79.0 g / 147.90 g x 100

Percent yield = 53.4%

8 0

3 years ago

Read 2 more answers

If the football indoors had a volume of 5.33 L at 21degrees celsuis, what is the volume of the football outside where the temp i

nata0808 [166]

Answer:

5.13 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 5.33 L

Initial temperature (T₁) = 21 °C

Final temperature (T₂) = 10 °C

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 21 °C

Initial temperature (T₁) = 21 °C + 273

Initial temperature (T₁) = 294 K

Final temperature (T₂) = 10 °C

Final temperature (T₂) = 10 °C + 273

Final temperature (T₂) = 283 K

Finally, we shall determine the final volume. This can be obtained as follow:

Initial volume (V₁) = 5.33 L

Initial temperature (T₁) = 294 K

Final temperature (T₂) = 283 K

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

5.33 / 294 = V₂ / 283

Cross multiply

294 × V₂ = 5.33 × 283

294 × V₂ = 1508.39

Divide both side by 294

V₂ = 1508.39 / 294

V₂ = 5.13 L

Thus, the new volume of the football is 5.13 L

3 0

3 years ago