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MatroZZZ [7]
3 years ago
14

What happens when a wave hits an object?

Chemistry
1 answer:
pshichka [43]3 years ago
8 0
Answer: the wave is reflected
explaination: in which, reflected stately happens when a wave strikes an object
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Hich statement describes the process of fusion, but not the process of fission?
lesantik [10]

The answer is A. this process is only in the research phase

The process of fusion involves merging of atomic nuclei to form heavier nuclei resulting in the release of enormous amounts of energy. Fusion takes place when two low mass isotopes, typically isotopes of hydrogen, unite under conditions of extreme pressure and temperature. Scientists continue to work on controlling nuclear fusion in an effort to make a fusion reactor to produce electricity. However, progress is slow due to challenges with understanding how to control the reaction in a contained space.






4 0
4 years ago
There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g

n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
  • n(\text{Hg atoms}) = 0.6018 \; g  / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol

Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.016 \; g  / 16 \; g \cdot mol^{-1}= 0.001 \; mol
  • n(\text{Hg atoms}) = 0.4012 \; g  / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol

n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

8 0
3 years ago
Wendy made the following diagram shown to represent the solar eclipse.
Pavlova-9 [17]
The moon should be between the sun and Earth
7 0
3 years ago
Read 2 more answers
The kinetic molecular theory describes the behavior of gases in terms of particles in?
Dominik [7]
The answer is motion, this is what I would go with because when you are dealing with gases it puts motion in the term of particles.
6 0
3 years ago
What’s the answer please gelp
romanna [79]

Answer:

Option A. 1.8×10²⁴ molecules.

Explanation:

Data obtained from the question include:

Number of mole of methane = 3 moles

Number of molecules of methane =?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules.

Thus, 1 mole of methane equally contains 6.02×10²³ molecules.

With the above information in mind, we can obtain the number of molecules in 3 moles of methane as follow:

1 mole of methane contains 6.02×10²³ molecules.

Therefore, 3 moles of methane will contain = 3 × 6.02×10²³ = 1.8×10²⁴ molecules.

Thus, 3 moles of methane contains 1.8×10²⁴ molecules.

4 0
3 years ago
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