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Elena-2011 [213]
3 years ago
5

Frost wedging in a sentence

Physics
1 answer:
Brrunno [24]3 years ago
7 0
 example "How would i put frost wedging in a sentence?" LOL hope this helped
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What is the kinetic energy of a 55 kilogram skier traveling at meters per second
Rasek [7]
How many meters per second was it traveling
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4 years ago
What is the disorder caused when cells lose the ability to control growth and continue to divide?
8090 [49]
The answer is cancer that is the reason there is no complete cue in people
7 0
3 years ago
What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave
Llana [10]

Explanation:

It is given that,

The thinnest soap film appears black when illuminated with light with a wavelength of 535 nm, \lambda=5.35\times 10^{-7}\ m

Refractive index, \mu=1.33

We need to find the thickness of soap film. The soap film appear black means there is an destructive interference. The condition for destructive interference is given by :

2t=m\dfrac{\lambda}{\mu}

t = thickness of film

m = 0,1,2....

\mu = refractive index

t=m\dfrac{\lambda}{2\mu}

t=\dfrac{\lambda}{2\mu}

For thinnest thickness, m = 1

t=1\times \dfrac{5.35\times 10^{-7}\ m}{2\times 1.33}

t=2.01\times 10^{-7}\ m

Hence, this is the required solution.

6 0
3 years ago
s) A body of mass 2 kilograms moves on a circle of radius 3 meters, making one revolution every 5 seconds. Find the magnitude of
jeyben [28]

Answer:

Centripetal force acting on the body = 9.47 N

Explanation:

Mass of body, m = 2 kg

Radius, r = 3 m

It makes one revolution in 5 seconds.

        Period, T = 5 s

        \texttt{Angular velocity, }\omega =\frac{2\pi }{T}=\frac{2\pi }{5}=1.256rad/s

Centripetal force, F = mrω²

                        F = 2 x 3 x 1.256² = 9.47 N

Centripetal force acting on the body = 9.47 N

8 0
3 years ago
A sinewave has a period (duration of one cycle) of 645 μs (microseconds). What is the corresponding frequency of this sinewave,
Oliga [24]

The corresponding frequency of this sinewave, in kHz, expressed to 3 significant figures is: 155 kHz.

<u>Given the following data:</u>

  • Period = 645 μs

Note: μs represents microseconds.

<u>Conversion:</u>

1 μs = 1 × 10^-6 seconds

645 μs = 645 × 10^-6 seconds

To find corresponding frequency of this sinewave, in kHz;

Mathematically, the frequency of a waveform is calculated by using the formula;

Frequency = \frac{1}{Period}

Substituting the value into the formula, we have;

Frequency = \frac{1}{645 * 10^-6}

Frequency = 1550.39 Hz

Next, we would convert the value of frequency in hertz (Hz) to Kilohertz (kHz);

<u>Conversion:</u>

1 hertz = 0.001 kilohertz

1550.39 hertz = X kilohertz

Cross-multiplying, we have;

X = 0.001 × 1550.39

X = 155039 kHz

To 3 significant figures;

<em>Frequency = 155 kHz</em>

Therefore, the corresponding frequency of this sinewave, in kHz is 155.

Find more information: brainly.com/question/23460034

6 0
3 years ago
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