D = distance between th two trains at the start of the motion = 100 miles
V = speed of the faster train towards slower train = 60 mph
v = speed of the slower train towards faster train = 40 mph
t = time taken by the two trains to collide = ?
time taken by the two trains to collide is given as
t = D/(V + v)
t = 100/(60 + 40) = 1 h
v' = speed of the bird = 90 mph
d = distance traveled by the bird
distance traveled by the bird is given as
d = v' t
d = 90 x 1
d = 90 miles
The index of refraction of light varies from color to color. TRUE.
<h3><u>Answer;</u></h3>
Period = 1/17 seconds
<h3><u>Explanation;</u></h3>
- Wavelength is related to period by the expression:
<em>speed = wavelength / period
</em>
- If we are given the speed, then we can easily calculate the period at the wavelength of 20 m.
<em>Given the speed of sound wave as 340 m/s </em>
<em>Period = Wavelength/ speed</em>
<em> = 20 m/340 m/s</em>
<em> </em><u><em>= 1/17 seconds</em></u>
The forces of attraction between water molecules and the glass walls and within the molecules of water themselves are what enable the water to rise in a thin tube immersed in water.
<h3>What is force?</h3>
Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Surface or interfacial forces lead to capillarity. The forces of attraction between the water molecules and the glass walls and among the water molecules themselves are what causes the water in a thin tube submerged in water to rise.
Hence, the water rises up a thin capillary tube can be explained by Newton's third law.
To learn more about the force refer to the link;
brainly.com/question/26115859#SPJ1
#SPJ1
Explanation:
It is given that,
The acceleration of the toboggan, ![a=1.8\ m/s^2](https://tex.z-dn.net/?f=a%3D1.8%5C%20m%2Fs%5E2)
Initial speed of the toboggan, u = 0
We need to find the distance covered by the toboggan. Using the second equation of motion as :
![s=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
At t = 1 s
![s=\dfrac{1}{2}\times 1.8\times 1^2](https://tex.z-dn.net/?f=s%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%201.8%5Ctimes%201%5E2)
![s_1=0.9\ m](https://tex.z-dn.net/?f=s_1%3D0.9%5C%20m)
At t = 2 s
![s=\dfrac{1}{2}\times 1.8\times 2^2](https://tex.z-dn.net/?f=s%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%201.8%5Ctimes%202%5E2)
![s_2=3.6\ m](https://tex.z-dn.net/?f=s_2%3D3.6%5C%20m)
At t = 3 s
![s=\dfrac{1}{2}\times 1.8\times 3^2](https://tex.z-dn.net/?f=s%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%201.8%5Ctimes%203%5E2)
![s_3=8.1\ m](https://tex.z-dn.net/?f=s_3%3D8.1%5C%20m)
Hence, this is the required solution.