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3 years ago

If a charge at 60c flow in a conductor for 30 second then the current that flow in a conductor is

Physics

1 answer:

saw5 [17]3 years ago

3 0

Explanation:

<h3>Given</h3>

- Charge = 60c

time = 30 sec

current

<h3>Solution </h3>

Current = Charge/time

I = V/T

I = 60/30

I = 2 ampere

More to know -

I = Current

V = Charge

T = Time

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A positive and a negative charge are released from rest in vacuum. They move toward each other. As they do: A positive and a neg

Pachacha [2.7K]

Answer:

A negative potential energy becomes more negative

Explanation:

Let the charges be - Q₁ and Q₂ . Let the distance between them be d .

Potential energy = k -Q₁x Q₂ / R

= - KQ₁ Q₂ / R

Now if the magnitude of R decreases , the magnitude of potential energy increases . So we see that the negative potential energy becomes more negative .

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4 years ago

Scientists would like to learn more about the seismic activity that occurs on Earth’s surface. They are set to take a journey to

Ludmilka [50]

Answer:

the questions they could ask would be:

how much will the temperature change?

how much pressure will there be?

how durable does the equipment need to be?

how do we know if we will run into a water pocket or a magma pocket?

Explanation:

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3 years ago

A jet aircraft with a mass of 4,475 kg has an engine that exerts a force (thrust) equal to 60,800 N. (a) What is the jet's accel

BartSMP [9]

Answer:

a) 13.59 m/s²

b) 67.95 m/s

c) 169.875 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass

Force

$F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{60800}{4475}\\\Rightarrow a=13.59\ m/s^2$

Acceleration of the jet is 13.59 m/s²

$v=u+at\\\Rightarrow v=0+13.59\times 5\\\Rightarrow v=67.95\ m/s$

Velocity attained at 5 seconds is 67.95 m/s

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{67.95^2-0^2}{2\times 13.59}\\\Rightarrow s=169.875\ m$

Distance traveled in the 5 seconds is 169.875 m

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3 years ago

Read 2 more answers

A transformer has 1000 turns in the primary coil and 100 turns in the secondary coil. If the primary coil is connected to a 120

Marianna [84]

Answer:

The voltage on the secondary is 12 V while the current is 0.5 A.

Explanation:

A transformer works by changing the level of the voltage and current on a circuit using a magnetic field and two coils. The ratio by wich they are changed is dependant on the ratio of turns between the primary and secondary of the transformer. In this case we have a ratio for the voltage of:

ratio = (turns on the secondary)/(turns on the primary)

ratio = 100/1000 = 0.1

So in this case the voltage delivered to the primary will be multiplied by 0.1. We can now calculate the voltage on the secondary:

Voltage secondary = Voltage primary* ratio = 120*0.1 = 12 V

The transformer maintains roughly the same power output on both sides, since the power output on a electric circuit is given by the product of the voltage by the current on that circuit, to maintain the same power when the voltage has been droped the current must be raised by the same ratio. So we have:

Current secondary = Current primary*(1/ratio) =0.05*(1/0.1) = 0.5 A

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3 years ago

A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m an

Ber [7]

Complete Question

A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t)−(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 7.10 m/s. What is the x-coordinate of the object when t = 10.0 s?

Answer:

The position of the object at t = 10s is $X = 38.3 \ m$