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galina1969 [7]
3 years ago
6

What is the formula (equation) for momentum?

Mathematics
2 answers:
enot [183]3 years ago
6 0

Answer:

The answer is p = m×v.

Step-by-step explanation:

The formula of momentum is p = m×v where m is the mass of object and v is the velocity of an object.

lesya [120]3 years ago
3 0

Answer:

p=mv

Step-by-step explanation:

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I need an answer soon. Thanks!
Anika [276]
The answer is, x-5 equals to 0. So x equals to 5. So your answer is 5.
5 0
3 years ago
There are 80 people waiting to tour the science museum. The tour guide takes 4 groups of 16 people each. The remaining people wi
Anna11 [10]

Answer:

16 people

Step-by-step explanation:

Given that :

Number of people to tour = 80

Number per group = 16

Number of groups = 4

Total number of people who make up the entire groups :

Number per group * number of groups

16 * 4 = 64

The number of people in the last tour group :

80 - 64

= 16 people

7 0
3 years ago
An element with mass 590 grams decays by 19. 5% per minute. How much of the element is remaining after 15 minutes, to the neares
solmaris [256]

Answer:

Step 1

Formulate a recursive sequence modeling the number of grams after n  minutes.

we have that

100%-17.1%-------------- > 82.9%------------> 0.829

a(n) = 780*[0.829^n]

for n=19 minutes

a(19)=780*[0.829^(19)]=22.1121 g---------------> 22.1 g

the answer is 22.1 g

Step-by-step explanation:

5 0
2 years ago
Use the Midpoint Rule with n = 5 to estimate the volume V obtained by rotating about the y-axis the region under the curve y = 1
velikii [3]

Using the shell method, the volume is given exactly by the definite integral,

2\pi\displaystyle\int_0^1x(1+9x^3)\,\mathrm dx

Splitting up the interval [0, 1] into 5 subintervals gives the partition,

[0, 1/5], [1/5, 2/5], [2/5, 3/5], [3/5, 4/5], [4/5, 5]

with left and right endpoints, respectively, for the i-th subinterval

\ell_i=\dfrac{i-1}5

r_i=\dfrac i5

where 1\le i\le5. The midpoint of each subinterval is

m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}{10}

Then the Riemann sum approximating the integral above is

2\pi\displaystyle\sum_{i=1}^5m_i(1+9{m_i}^3)\frac{1-0}5

\dfrac{2\pi}5\displaystyle\sum_{i=1}^5\left(\frac{2i-1}{10}+9\left(\frac{2i-1}{10}\right)^4\right)

\dfrac{2\pi}{5\cdot10^4}\displaystyle\sum_{i=1}^5\left(16i^4-32i^3+24i^2+1992i-999\right)=\frac{112,021\pi}{25,000}\approx\boxed{14.08}

(compare to the actual value of the integral of about 14.45)

3 0
3 years ago
Simplify the fraction completly<br> 60/100
nignag [31]

Answer: 3/5

Step-by-step explanation: simplified completely

6 0
3 years ago
Read 2 more answers
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