3 years ago

Identify the species that was reduced in the titration reaction shown below. Justify your answer in terms of oxidation numbers.

Chemistry

1 answer:

Harrizon [31]3 years ago

8 0

Answer:

MnO₄⁻ is species reduced as manganese gains 5e⁻ and is reduced to Mn⁺²

Explanation:

MnO₄⁻ + 5e⁻ => Mn⁺²

Mn + 4O = -1

Mn + 2(-2) = - 1

Mn = +7

Mn = +7 gains 5e⁻ => Mn = +2

You might be interested in

Blank occurs when water molecules at the surface of a pool have enough kinetic energy that the attractive forces holding them to

Hunter-Best [27]

Evaporation occurs when water molecules at the surface of a pool have enough kinetic energy that the attractive forces holding them to the liquid can be overcome

6 0

3 years ago

The form of oxygen that combines three oxygen atoms to each molecule, is found in the stratosphere and shields out harmful UV ra

Dmitry_Shevchenko [17]

This form of the oxygen molecule is Ozone, O3.

7 0

3 years ago

What kind of chemical bonds are represented by the product in the following diagram?

katovenus [111]

The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.

4 0

3 years ago

What method would you use to find the volume of an irregularly shaped object?

dimulka [17.4K]

Displacement, usually the method that is used to measure the volume of an irregularly shaped object.

4 0

4 years ago

Two objects of equal mass have a force of gravity of 6 N between them. Imagine the mass of one is cut in half and the other stay

Alenkasestr [34]

Answer:

F' = 3 N

Explanation:

Given that,

Two objects of equal mass have a force of gravity of 6 N between them.

If the mass of one is cut in half and the other stays the same such that,

m₁' = m₁ and m₂' = (m₂/2)

We need to find the new force. The gravitational force between two objects is given by :

$F=G\dfrac{m_1m_2}{r^2}$

We have, F = 6 N

New force,

$F'=G\dfrac{m_1'm_2'}{r^2}\\\\F'=\dfrac{Gm_1\times \dfrac{m_1}{2}}{r^2}\\\\=\dfrac{1}{2}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{2}\\\\F'=\dfrac{6}{2}\\\\F'=3\ N$

So, the new force becomes 3 N.

3 0

3 years ago