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jek_recluse [69]
3 years ago
7

You have prepared a saturated solution of x at 20∘c using 39.0 g of water. how much more solute can be dissolved if the temperat

ure is increased to 30∘c? express your answer with the appropriate units.
The following table gives the solubility of solute X in water at two different temperatures:

Temperature
(∘C) Solubility
(g/100 g H2O)
20 11.0
30 23.0
Chemistry
1 answer:
AleksAgata [21]3 years ago
3 0

for 39g water solute dissolved at 20C = solubility ( g/ 100 g H2O ) × mass of water = ( 11g / 100g H2O ) × 39g H2O = 4.29 g

amount of solute dissolved at 30 C =

               =  23 / 100 * 39 = 8.97 g

Amount of extra solute dissolved = 8.97 - 4.29 = 4.7 g

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If the CaCO3 weighed 983 g and the CaO weighed 551 g, how many grams of CO2 were formed in the reaction?
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Answer:

The answer to your question is 432 g of CO₂

Explanation:

Data

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CO₂ = ?

Balanced reaction

                               CaCO₃ (s)   ⇒   CaO (s)   +  CO₂ (g)

This reaction is balanced, to solve this problem just remember the Lavoisier Law of conservation of mass that states that the mass of the reactants is equal to the mass of the products.

                    Mass of reactants = Mass of products

                    Mass of CaCO₃   = Mass of CaO + Mass of CO₂

Solve for CO₂

                    Mass of CO₂  = Mass of CaCO₃ - Mass of CaO                    

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Simplification

                     Mass of CO₂ = 432 g                        

         

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