Question

You have prepared a saturated solution of x at 20∘c using 39.0 g of water. how much more solute can be dissolved if the temperature is increased to 30∘c? express your answer with the appropriate units.
The following table gives the solubility of solute X in water at two different temperatures:

Temperature
(∘C) Solubility
(g/100 g H2O)
20 11.0
30 23.0

Answer 1

for 39g water solute dissolved at 20C = solubility ( g/ 100 g H2O ) × mass of water = ( 11g / 100g H2O ) × 39g H2O = 4.29 g

amount of solute dissolved at 30 C =

               =  23 / 100 * 39 = 8.97 g

Amount of extra solute dissolved = 8.97 - 4.29 = 4.7 g