Answer:
I. First number, a = 40.
II. Second number, b = 50.
III. Third number, c = 120.
Step-by-step explanation:
Let the three numbers be a, b and c respectively.
Given the following data;
Translating the word problem into an algebraic equation, we have;
a + b + c = 210
b = a + 10
c = 3a
Substituting the value of b and c into the equation, we have;
a + a + 10 + 3a = 210
5a + 10 = 210
5a = 210 - 10
5a = 200
a = 200/5
<em>a = 40</em>
To find the value of b;
b = a + 10
b = 40 + 10
<em>b = 50</em>
To find c
c = 3a
c = 3*40
<em>c = 120</em>
Answer:
30y+14
Step-by-step explanation:
add the values of all the sides together: (5y+4) + (5y+4) + (10y+3) + (10y+3) = (5y + 5y + 10y + 10y) + (4 + 4 + 3 + 3)= 30y + 14
The answer is 2.756 in pound's
F(x)=5x
normal domain: all real numbers
practical domain: <span>all positive integers
</span>becasue we can substituent with any positive integer in the place of x
This is pretty much 75% of 55.5 which is 41.625. Rounding that up would make $41.63.
