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3 years ago

Five friends shared 1/5 kilogram of nuts equally. What fraction of a kilogram of nuts did each friend eat?

Mathematics

1 answer:

Rama09 [41]3 years ago

3 0

Answer:

they each got 1/5.there are five friends, if they share 1/5 then each gets 1/5 of nuts.

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Quadrilateral ABCD is a a square and the length of BE is 6 cm. What is the length of AC?

Aloiza [94]

The answer is: 12 centimeters.

The explanation is shown below:

1. By definition, all four sides of the square are equal and the diagonals are equal too.

2. Keeping the information above on mind, you know that AC and BD are equal:

$AC=BD$

3. Then, the length of BD is twice BE. So, you can calculate it as following:

$BD=2BE$

$BD=2(6cm)\\BD=12cm$

4. Therefore, the lenght of AC is:

$AC=12cm$

5 0

3 years ago

Which transfromations tranforms the graph of f(x)=x^2 to the graph of g(x)=(x+4)^2?

wariber [46]

Greetings from Brasil...

In function F(X) = X², if we replace X with X + 4 we will have exactly function G(X) = (X + 4)²

So, just replace X for X + 4..... This will be responsible for translating 4 units to the left, because:

F(X) = X²

F(X + 4) = (X + 4)²

F(X + 4) ⇔ F(X + k) see below

We know that the translations are established as follows:

→ Horizontal

F(X + k) ⇒ k units to the left

F(X - k) ⇒ k units to the right

see more:

brainly.com/question/17163323

4 0

3 years ago

PLEASE HELP ME!!!

allsm [11]

Answer: 25??

Step-by-step explanation: $8×25= $200

i dont know if thats your answer thats just all the adults that could get in for $200.

-Zoey Lee

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7 0

3 years ago

Need help on this question

ololo11 [35]

45 degree between Oak street and Elm Street.

4 0

3 years ago

Suppose that salaries for recent graduates of one university have a mean of $25,700 with a standard deviation of $1350. Using Ch

sergeinik [125]

Answer:

75% of the data will reside in the range 23000 to 28400.

Step-by-step explanation :

To find the range of values :

We need to find the values that deviate from the mean. Since we want at least 75% of the data to reside between the range therefore we have,

$1 - \frac{1}{k^2} =\frac{75}{100}$

Solving this, we would get k = 2 which shows the value one needs to find lies outside the range.

Range is given by : mean +/- (z score) × (value of a standard deviation)

⇒ Range : 25700 +/- 2 × 1350

⇒ Range : (25700 - 2700) to (25700 + 2700)

Hence, 75% of the data will reside in the range 23000 to 28400.

3 0

3 years ago