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Tanzania [10]
3 years ago
14

The angle of elevation to the top of a 20-story skyscraper is measured to be 2 degrees from a point on the ground 5,280 feet fro

m the building. What is the height of the skyscraper to the nearest hundredth foot?

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0
<span>Height of the skyscraper to the nearest hundredth foot
= 5280 Tan(2)
= </span>184.38
Vlad1618 [11]3 years ago
3 0

Answer:

184.38\ ft

Step-by-step explanation:

we know that

In a right triangle the tangent function of an angle \theta is equal to divide the opposite side to the angle \theta by the adjacent side to the angle \theta

In this problem we have

\theta=2\°

adjacent\ side=5,280\ ft

Let

h-----> the opposite side to the angle \theta (represent the height)

so

tan(2\°)=h/5,280

h=5,280*tan(2\°)=184.38\ ft

see the attached figure to better understand the problem

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