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Zanzabum
2 years ago
13

79 to the power of 3 = pi times 25 times h divided by 3

Mathematics
1 answer:
dolphi86 [110]2 years ago
7 0

Answer:

h=\frac{79^3 * 3}{25\pi}

Step-by-step explanation:

Here, we have to find the value for h, in terms of \pi.

Assuming The equation is:

79^3=\frac{\pi*25*h}{3}

We cross multiply to get:

79^3=\frac{\pi*25*h}{3}\\79^3 * 3 = 25\pi h\\

Now, we divide both sides by 25\pi to get an expression of h in terms of \pi:

h=\frac{79^3 * 3}{25\pi}

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Lapatulllka [165]

Answer:

8) answer=5 9)answer=15

Step-by-step explanation:

all you have to do is replace in the following formula

\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}} =d

Where

X1: is the first number of the first point

Y1: is the second number of the first point

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you replace in the formula and solve

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4 0
2 years ago
What is an equation of the parabola with vertex at the origin and focus (0, 0.75)?
morpeh [17]

Answer:

x^{2} =3y

Step-by-step explanation:

Notice that the focus is a points on the vertical axis, that means the parabolla opens vertically, and has the form

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Because the parameter p is positive and equal to 0.75. Additionally, the vertex is at the origin, that's why the equation is this simple.

Replacing the parameter value, we have

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Therefore, the equation of a parabolla with vertex at the origin and focus at (0, 0.75) is x^{2} =3y.

8 0
3 years ago
A six-sided die with sides labeled 1 through 6 will be rolled once. Each number is equally likely to be rolled.
ivanzaharov [21]

Answer:

2/3

Step-by-step explanation:

The numbers greater then 2 are 3, 4, 5, 6

That's four numbers that are greater then two.

or 4/6, then you just reduce it by dividing by two on the top and bottom

4/2 =2

6/2 = 3                            so the answer is 2/3

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3 years ago
Michelle bought a gift priced at $5.00.she gave the store clerk $20.00.she received three bills as change.what bills did she rec
goblinko [34]
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3 years ago
Read 2 more answers
NEED MATH HELP ASAP
Dafna1 [17]

Answer:

2

Step-by-step explanation:

Divide the 2nd term by the 1st to find the common ratio or n.

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3 years ago
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