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densk [106]
4 years ago
14

|x+2|-3=9 please help!!! Solve twice!!! Two answers!!!

Mathematics
2 answers:
Over [174]4 years ago
6 0
×= 10 and ×= -14

Find x by simplifying both sides of the equation then isolate the variable.
Solnce55 [7]4 years ago
6 0

|x+2| - 3 = 9

Option 1:

x + 2 - 3 = 9

x - 1 = 9   <em>  add 1</em>

x = 9 + 1

x = 10

Option 2:

-(x+2) - 3 = 9  <em>Distribute "-" through the parenthesis </em>

-x - 2 - 3 = 9

-x - 5 = 9     <em>Add 5</em>

-x = 9 + 5

-x = 14   <em>Multiply by -1</em>

x = -14

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David runs on a track that is 1/4 mile long he completes it in 1/20 of an hour
posledela

Answer:

<h2> 5mile per hour</h2>

Step-by-step explanation:

Step one:

given data

distance= 1/4mile

time taken= 1/20 hour

Step two:

Required

speed

we know that speed is

speed= distance/time

substituting

speed= 1/4/1/20

speed=1/4*20/1

speeed=20/4

speed=5mile/hour

The option a sis correct, the speed is 5mile per hour

7 0
3 years ago
When x=12, y=8. Find x when y=12
Digiron [165]
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3 years ago
What is the area of a circle with a radius of 5
V125BC [204]
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5 0
3 years ago
Read 2 more answers
A total of 800 pre-sale tickets and tickets at the gate were sold to football city championship game. If the number of tickets s
Nitella [24]

The number of presale tickets sold is 271

<em><u>Solution:</u></em>

Let "p" be the number of presale tickets sold

Let "g" be the number of tickets sold at gate

<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>

Therefore,

Presale tickets + tickets sold at gate = 800

p + g = 800 ------ eqn 1

<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>

Therefore,

Number of tickets sold at gate = twice the number of pre-sale tickets - 13

g = 2p - 13 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 2 in eqn 1

p + 2p - 13 = 800

3p -13 = 800

3p = 800 + 13

3p = 813

p = 271

Thus 271 presale tickets were sold

4 0
4 years ago
The range R and the maximum height H of a projectile fired at an inclination θ
sergiy2304 [10]

Answer:

1370 feet (3 sf)

Step-by-step explanation:

(210)²×sin(2×45)/32.2

1369.565217

3 0
3 years ago
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