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densk [106]
3 years ago
14

|x+2|-3=9 please help!!! Solve twice!!! Two answers!!!

Mathematics
2 answers:
Over [174]3 years ago
6 0
×= 10 and ×= -14

Find x by simplifying both sides of the equation then isolate the variable.
Solnce55 [7]3 years ago
6 0

|x+2| - 3 = 9

Option 1:

x + 2 - 3 = 9

x - 1 = 9   <em>  add 1</em>

x = 9 + 1

x = 10

Option 2:

-(x+2) - 3 = 9  <em>Distribute "-" through the parenthesis </em>

-x - 2 - 3 = 9

-x - 5 = 9     <em>Add 5</em>

-x = 9 + 5

-x = 14   <em>Multiply by -1</em>

x = -14

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Steven is solving the equation 3(8−2x)+40=34. He begins with the following two steps.
STatiana [176]

Answer:

<h2>Add 24 and 40</h2>

Step-by-step explanation:

3(8 - 2x) + 40 = 34       <em>use the distributive property a(b + c) = ab+ ac</em>

3(8) + 3(-2x) + 40 = 34

24 - 6x + 40 = 34          <em>combine like terms</em>

-6x + (24 + 40) = 34      <em>Answer: Add 24 and 40</em>

-6x + 64 = 34            <em>subtract 64 from both sides</em>

-6x = -30          <em>divide both sides by (-6)</em>

x = 5

7 0
3 years ago
Read 2 more answers
What is p if 8/p = 3/14
anzhelika [568]
P/8=14/3
P=14*8/3
P=37.3333
4 0
3 years ago
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
brad wants to open a new saving account. he finds one that returns 3% on his investment each year.Use the varibles to write a fo
Vsevolod [243]

3% is the interest so you would do 3% of the investment plus the original investment so 3%×I=z and then z+I=the answer. sorry if this didnt help I'm new and I tried my best sorry!

3 0
3 years ago
write an equation in general form of the line passing through (3, -5) whose slope is the negative reciprocal of -1/4
IceJOKER [234]
Negative reciprocal means
-1/4 times x=-1 solve for x
multiply both sides by -4/1
x=-4
so slope=-4
y=mx+b
m=slope, b=y intercpet
y=-4x+b
input 3 for x and -5 for y
-5=-4(3)+b
-5=-12+b
add 12 to both sides
7=b
the equation in slope intercept form is y=-4x+7
that is my standard form
another standard form is
y+4x=7
4 0
3 years ago
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