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Rus_ich [418]
3 years ago
5

I need help with three math (algebra) problems?

Mathematics
1 answer:
Bumek [7]3 years ago
3 0
1.
A. (49-8)*2-16, 41*2-16, 82-16, 66, yep
B. 49-8*-14, 49+112, 161, nope
C. 7^(-16)-16, (1/(7^16))-16, nope
D. 49-16-16, 17, nope

A is answer


2.
2((a+b)²-b)
2((7+1)²-1)
2((8)²-1)
2(64-1)
2(63)
126
C is answer


4.
none of the options give the answer
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Answer:

In the division problem,

The number which is divided is called dividend,

While, the number which divides, is called divisor,

Let dividend = 150 ( a three digit number ),

Divisor = 15 ( a number between 10 and 12 ),

So, the problem would be,

150\div 15

In the below figure,

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Thus, there are such 10 boxes,

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WITCHER [35]

Answer:

the savings is 6000

Step-by-step explanation:

We are told that the ratio of savings to expenditure is 2: 8, that is, that person saves 2 when he spends 8.

They tell us to find the savings when the cost is 24,000, so we are left with:

24000 * 2/8 = 6000

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6 0
3 years ago
-377 = x - 1,000 i dont under stand it
Naddika [18.5K]

Answer:

\boxed {x = 623}

Step-by-step explanation:

Solve for the value of x:

-377 = x - 1,000

-Switch sides:

-377 = x - 1,000

x - 1,000 = -377

-Add 1,000 on both sides:

x - 1,000 + 1,000 = -377 + 1,000

\boxed {x = 623}

Therefore, the value of x is 623.

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Answer:

One example: 1.29

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