Answer:
A. Sandboxing
Explanation:
The best solution to apply for this task would be Sandboxing. This is a software management strategy that isolates applications from critical system resources and other programs. In doing so you effectively add a secondary security layer on top of the application in order to prevent any and all malware from entering and damaging your overall system. Thus effectively reducing the risk.
Hey!
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Definition:
A "for loop" is something used for repeating things over a list of items. For instance, a list or a dictionary.
Code:
colors = ["red", "green", "blue"]
for x in colors:
print(x)
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Definition:
A "while loop" is is something used for carrying out a set of lines that are true.
Code:
n = 1
while i < 4:
print(n)
n += 1
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Real-Life Example:
A real-life example would if I was a manager or boss for a company say that everyone was off a certain day. Like, if I said everyone was off for Christmas the 25th. If I had 1000 employees that would take a very long time to send an email to everyone. Instead of sending an email to everyone I can program code that uses "for loops" and "while loops" to create a message and send it to everyone.
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Hope This Helped! Good Luck!
Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m
